Methyl iodide can be produced by reacting hydro$-$iodic acid with an excess methanol via the reaction:

$HI+C{H}_{3}OHC{H}_{3}I+H_{2}O$

A typical process for the production of methyl iodide is indicated in the following figure. The feed to the reactor contains $2\mathrm{.}1$ moles $C{H}_{3}OH$ per $1$molHI. The single pass conversion of $HI$ is $50\%$ conversion and $90\%$ of the $H_{2}O$ entering the first separator leaves in stream $5.$ All compositions are in molar basis.

How many moles of $C{H}_3$I are produced per mole of fresh $HI$ feed?