Question
MIPS Assembly Language: Implement a MIPS assembly language program that defines main, and function1 procedures. The function1 is recursive and should be defined as: function1(n)
MIPS Assembly Language:
Implement a MIPS assembly language program that defines "main", and "function1" procedures.
The function1 is recursive and should be defined as:
function1(n) = (3*n) - 7 if n <= 4
= function1(n-2) + n*function1(n-4) - n + 2 otherwise.
The main asks a user to enter an integer for n and calls the function1 by passing the n value, then prints the result. If your program causes an infinite loop, press Control and 'C' keys at the same time to stop it.
C program that will ask a user to enter an integer, calls the function1, and prints the returned value from the function1.
// The function1 is a recursive procedure/function defined by: // function1(n) = (3*n) - 7 if n <= 4 // = function1(n-2) + n*function1(n-4) - n + 2 otherwise. int function1(int n) { if (n <= 4) { int ans1 = (3*n)-7; return ans1; } else { int ans1 = function1(n-2) + n*function1(n-4) - n + 2; return ans1; } } // The main calls function1 by entering an integer given by a user. void main() { int ans, n; printf("Enter an integer: "); // read an integer from user and store it in "n" scanf("%d", &n); ans = function1(n); // print out the solution computed by function 1 printf("The solution is: %d ", ans); return; }
The following is a sample output (user input is in bold):
Enter an integer: 9 The solution is: -208
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