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MIPS assembly language programming: write a MIPS program that loops through an integer array and counts how many odd and even integers are in the
MIPS assembly language programming: write a MIPS program that loops through an integer array and counts how many odd and even integers are in the array. High level code in C++ looks like:
int even = 0;
int odd = 0;
int length = 5;
int arr [5] = {1, 2, 3, 4, 5};
for(int i = 0; i < length; ++i) {
if(arr[i] % 2 == 0)
even++;
else
odd++;
}
Thank you very much for any help
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