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MIPS assembly language programming: write a MIPS program that loops through an integer array and counts how many odd and even integers are in the

MIPS assembly language programming: write a MIPS program that loops through an integer array and counts how many odd and even integers are in the array. High level code in C++ looks like:

int even = 0;

int odd = 0;

int length = 5;

int arr [5] = {1, 2, 3, 4, 5};

for(int i = 0; i < length; ++i) {

if(arr[i] % 2 == 0)

even++;

else

odd++;

}

Thank you very much for any help

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