Mole balance

$F_{A0}\frac{dx}{dV}=-r_A$

Rate law

$-r_A=k_A{C}_A{C}_B$

Stoichiometry

$C_A=C_{A0}(1-x)$

$C_B$~~$C_{B0}$

Combine

$-r_A=k_A{C}_{B0}{C}_{A0}(1-x)=k{C}_{A0}(1-x),k_A{C}_{B0}=k$

$\frac{dx}{dV}=\frac{-r_A}{F_{A0}}=\frac{k{C}_{A0}(1-x)}{C_{A0}{v}_0}$

$\frac{dx}{(1-x)}=\frac{k}{v_0}dV=kd$

$ln(\frac{1}{(1-x)})=k,x=1-$exp$(-k)$

$=\frac{0\mathrm{.}31d{m}^3}{0\mathrm{.}0033d\frac{m^3}{sec}},k=0\mathrm{.}01s^{-1}$

$x=0\mathrm{.}61$

I do not know why $$ kaCbo$=$k $>$