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Money is invested at two rates of interest. One rate is 9% and the other is 4%. If there is $1400 more invested at 9

Money is invested at two rates of interest. One rate is 9% and the other is 4%. If there is $1400 more invested at 9 % than at 4 %, find the amount invested at each rate if the total annual interest received is $880. Let x = amount invested at 9% and y = amount invested at 4%. Then the system that models the problem x = y + 1400 Solve the system by using the method of addition. 0.09x + 0.04y = 880 is Answer How to enter your answer (opens in new window) $ invested at 9 % invested at 4% Keypad Keyboard Shortcuts

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