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[MT2]18. For a particular isotope, the number of atoms that decay per hour follows a Poisson distribution. The rate of decay is = 3atoms per
[MT2]18. For a particular isotope, the number of atoms that decay per hour follows a Poisson distribution. The rate of decay is = 3atomsper hour. Let= the number of atoms that decayin two hours. Find(5 7).
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