Multiple objects & inclined plane example * 1 FN FT FT X B 15 kg 9.0 kg A FgA VFgB 33- What is the magnitude and direction of the acceleration of the 9.0 kg block? (Neglect friction on the incline. ) EFA = mAa = FT - FgA EFX = mBa = FgBx - FT mAa = FT - FgA ma + mAg = mBg sin 330 - mBa ma + mBa = mBg sin 330 - mag mBa = FgBx - FT FT = mAa + FgA a(mA + mB) = mBg sin 330 - mag FT = FgBx - mBa FT = ma + mag meg sin 330 - mag FT = mBg sin 33 - mBa a = mA + mB (15 kg) (9.8 m/s2) sin 33 - (9.0 kg) (9.8 m/s2) a = 9.0 kg + 15 kg a = -0.34 m/s2 Block A has a downward acceleration of 0.34 m/$9