my answer: use normal distribution

E(X)=np=230*0.55=126.5

use 0.55 to find the x of standard normal distribution 0.13 from the table

0.13= (230-126.5)/SD, SD=795, (127-126.5)795=0.0006,(124-126.5)795=-0.003

P(127)=0.5000 ,P(124)=0.5000 , P(123

I know that my calculation is wrong, but I can't think of the correct solution. You can give some hints.

given a sample size of 230 from a large population with a constant probability of success of 0.55, what is the probability if finding between 123 and 128 items(that is,124, 125, 126,127)?