MY NOTES ASK YOUR TEACHER 11. [0/2 Points] DETAILS PREVIOUS ANSWERS SERPSE10 9.5.OP.018. 1/6 Submissions Used m2 As shown in the figure, a wooden ball with mass m2 is initially at rest on a horizontal, frictionless table. A second wooden ball with mass m moving with a speed 2.00 m/s, collides with m2" Assume moves initially along the +x-axis. After the collision, m moves with speed 1.00 m/s at an angle of 0 = 54.0 to the positive x-axis. (Assume m = 0.200 kg and = 0.300 kg.) m1 a m After the collision Vif l; sin 6 Ulf cos Before the collision Vi Uof cos Uf sin mq *2f b (a) Determine the speed (in m/s) of the 0.300 kg ball after the collision. 1.24 Write conservation of momentum equations in the x-and y-directions, and solve for p. Use your result to calculate the final speed of m2. m/s (b) Find the fraction of kinetic energy transferred away or transformed to other forms of energy in the collision. |AKI Ki = 0.1734 AKI Calculate the initial and final kinetic energies of the system, then apply flost Note that the initial kinetic energy is due only to m, because m2 is initially at rest. K; 12. [-/2 Points] DETAILS SERPSE10 9.5.OP.019. 0/6 Submissions Used MY NOTES ASK YOUR TEACHER An object of mass 2.99 kg, moving with an initial velocity of 5.06 1 m/s, collides with and sticks to an object of mass 2.22 kg with an initial velocity of -3.54 m/s. Find the final velocity of the composite object. V + m/s Need Help? Read It Watch It 13. [0/2 Points] DETAILS PREVIOUS ANSWERS SERPSE10 9.5.OP.020.MI. 1/6 Submissions Used MY NOTES ASK YOUR TEACHER A billiard ball moving at 5.20 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 4.31 m/s at an angle of 34.0 with respect to the original line of motion. Assuming an elastic collision (and ignoring friction and rotational motion), find the struck ball's velocity after the collision. magnitude direction 2.3 Check the initial and final kinetic energies. You will find that your final kinetic energy is not equal to the initial kinetic energy. m/s x 320 There are three equations relating the final velocities to the initial velocities (two from momentum conservation and one from energy conservation), but we only have two unknowns (the final speed and direction of the second ball). You thus have some flexibility in choosing equations to work with. (with respect to the original line of motion) Need Help? Read It Master It