MY NOTES Three different bacteria are cultured in one environment and feed on three nutrients Each individual of species I consumes 1 unit of each of the first and second nutrients and 2 units of the third nutrient Each individual of species II consumes 2 units of the first nutrient and 2 units of the third nutrient Each individual of species III consumes 2 units of the first nutrient 3 units of the second nutrient and 5 units of the third nutrient If the culture is given 5100 units of the first nutrient 7500 units of the second nutrient and 12 600 units of the third nutrient how many of each species can be supported such that all of the nutrients are consumed Let x species I y species II and z species III If there are infinitely many solutions express your answers in terms of z as in Example 3 x y z where 2400 z 2500