MY SCF Home: State College o X "Ch 8 homework - PHY2049, se x B A 4.50pF capacitor is connecte x *Homework Help - Q&A from Or x + C webassign.net/web/Student/Assignment-Responses/submit?dep=32016561&tags=autosave#question3807141_5 A 4.50 PF capacitor is connected in series with a 3.00 pF capacitor and a 610 V potential difference is applied across the pair. (a) What is the charge on each capacitor (in nC)? 4.50 pF capacitor 2.745 X nc 3.00 PF capacitor Inc (b) What is the voltage across each capacitor (in V)? 4.50 PF capacitor V 3.00 PF capacitor Additional Materials Reading Submit Answer 7. [-/1 Points] DETAILS OSUNIPHYS1 25.2.P.033. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Find the total capacitance (in UF) of this combination of series and parallel capacitors shown below. 19 UF = 5.5 UF = 0.90 HF Additional Materials Reading Submit Answer 8. [-/2 Points] DETAILS OSUNIPHYS1 25.2.P.035. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER What total capacitances (in NF) can you make by connecting a 5.75 JF and a 9.00 JF capacitor together? smaller value larger value Additional Materials Reading Submit Answer 9. [-/1 Points] DETAILS OSUNIPHYS1 25.2.P.037. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Find the net capacitance (in UF) of the combination of series and parallel capacitors shown below. 7 0.65 HF 12 UF