n a random sample of 49 trout, the average weight is 2 pounds, with standard deviation s = .5 pounds

Find:

Flag question: Question 1Question 18pts

Sample mean =

Group of answer choices

.5 pounds

.05 pounds

3 pounds

2 pounds

Flag question: Question 2Question 28pts

Standard Error of the sample mean =

Group of answer choices

.03

.01

.50

.07

Flag question: Question 3Question 38pts

Margin of error for 95% confidence =

Group of answer choices

.5

1

.02

.14

Flag question: Question 4Question 48pts

95% confidence interval for the population mean, :

Group of answer choices

2 .5

3 .12

2 .14

3 .50

Flag question: Spacer

A researcher believes that taking vitamin E reduces the severity of colds. 100 participants are randomly assigned so that 50 are in the experimental group (take vitamin E) and 50 are in the control group (take a placebo). Over the course of a year the lengths of each cold for all the participants are recorded, with the following results:

Vitamin E

= 4days

s1= 3 days

Control Group

= 7 days

s2= 5 days

Testing at significance level a = .05, Find:

Flag question: Question 5Question 58pts

H0and Ha:

Group of answer choices

H0: 1< 2

Ha: 1= 2

H0: 1= 4

Ha: 1< 4

H0: 1= 2

Ha: 1< 2

H0: 1= 4

Ha: 2 = 7

Flag question: Question 6Question 68pts

standard error of difference between sample means (S.E.) =

Group of answer choices

.82

.63

4.5

.4

Flag question: Question 7Question 78pts

Z =

Group of answer choices

-4.74

-7

-3.64

2.1

Flag question: Question 8Question 88pts

p-value =

Group of answer choices

.0001

.05

.9999

1

Flag question: Question 9Question 98pts

Conclusion:

Group of answer choices

do not reject H0

not enough information to decide

vitamin E is unsuccessful

reject H0

Flag question: Spacer

Here is some data from a random sample.

X: -3, 6, 7, 9, 1

Find:

Flag question: Question 10Question 108pts

mean, median =

Group of answer choices

mean = 20, median = 4

mean = 3, median = 4

mean = 4, median =6

mean = 3, median = 7

Flag question: Question 11Question 118pts

standard deviation =

Group of answer choices

24

3.63

4.9

16.5

Flag question: Spacer

In a certain city, 25% of senior citizens have used Uber. To see if an advertising campaign was effective, a researcher samples 200 senior citizens and finds that 70 have used Uber.

Testing at significance level = .05, find:

Flag question: Question 12Question 128pts

H0and Ha:

Group of answer choices

H0: p = .20

Ha: p > .20

H0: p = .25

Ha: p >.25

H0: p = .20

Ha: p < .20

H0: p = .15

Ha: p > .15

Flag question: Question 13Question 138pts

Sample proportion =

Group of answer choices

.35

.15

.70

.20

.40

Flag question: Question 14Question 148pts

Standard error (S.E.) assuming H0is true =

Group of answer choices

.85

.0006

.20

.03

Flag question: Question 15Question 158pts

z-value =

Group of answer choices

.05

2.0

3.27

.025

Flag question: Question 16Question 168pts

p-value =

Group of answer choices

.05

.02275

.0005

.9991

Flag question: Question 17Question 178pts

Conclusion:

Group of answer choices

reject H0

do not reject H0

.05 chance advertising campaign was effective

50-50 chance advertising campaign was effective

Flag question: Spacer

A coin is tossed five times. You bet $1 that heads will come up on all five tosses. If this happens, you win $20. Otherwise, you lose your $1 bet.

Find:

Flag question: Question 18Question 188pts

P(you win) =

Group of answer choices

1/32

1/4

1/16

1/8

Flag question: Question 19Question 198pts

P(you lose) =

Group of answer choices

1/2

15/32

3/4

31/32

Flag question: Question 20Question 208pts

Average winnings, , =

Group of answer choices

$.66

$-.50

0

-$.34

Flag question: Spacer

Weights of owls in a certain region are normally distributed with = 5 pounds and = 1 pound. Let X be the weight of a randomly selected owl.

Find:

Flag question: Question 21Question 218pts

P(X > 7) =

Group of answer choices

.16

.025

.975

.84

Flag question: Question 22Question 228pts

P(4

Group of answer choices

.05

.997

.68

.95

Flag question: Spacer

Some X, Y data are positively correlated with r = 0.7. Also:

=4	sx= 2
= 5	sy= 6

Flag question: Question 23Question 238pts

Find the equation for the regression line

Group of answer choices

y = -5 + .8x

y = -1.4 + 1.6x

y = -3.4 +2.1x

y = 4 + .8x

Flag question: Question 24Question 248pts

If x = 2, predict y =

Group of answer choices

5.6

1.8

.8

4.6

Flag question: Question 25Question 258pts

coefficient of determination =

Group of answer choices

.49

.7

.64

.36