n, mol TC An n = 49.00 mol mixture of XEI = 0.3200 mol ethanol/mol and xwi = 0.6800 mol water/mol at T = 13.0 C enters an evaporator. A liquid and a vapor stream leave the evaporator, both at T2 = 85.0 C. The vapor product stream is composed of XE2 = 0.4590 mol ethanol/mol and Xw2 = 0.5410 mol water/mol. The liquid product stream is composed of XE3 = 0.1130 mol ethanol/mol and Xw3 = 0.8870 mol water/mol. e mol E/mol w mol W/mol Evaporator QkJ n, mol C Determine the amount of heat supplied by the evaporator by following the steps in this question. Use the given equation to describe the heat capacity of liquid ethanol 000 mol E/mol xw, mol W/mol Cp = 5.57 x 10-4T + 103.1 x 10-3 where T is in degrees Celsius and Co is in kJ/mol.C). n, mol Y, C What is n2, the moles of vapor product stream? mol E/mol tw, mol W/mol n2 = mol What is nz, the moles of liquid product stream? n3 = mol Calculate the specific enthalpy of the streams. Choose a reference state of the conditions of the incoming stream to simplify the calculations. Refer to the table for variable names. References: ethanol (liquid, 13.0C, 1 atm), water (liquid, 13.0 C, 1 atm). Substance nin (mol) Hin (kJ/mol) nout (mol) out (kJ/mol) Ethanol (1) (n)(XED) 0 (n3) (XE3) Water (1) (n)(xwi) (n3) (x3) H2 Ethanol (v) (n2) (XE2) Water (v) (n2) (Xw2) 4 0 What is the specific enthalpy of liquid ethanol leaving the evaporator at 85.0 C? 1. h = II kJ/mol What is 2, the specific enthalpy of liquid water leaving the evaporator at 85.0 C? 2 = = kJ/mol What is 13, the specific enthalpy of ethanol vapor leaving the evaporator at 85.0 C? 3 = kJ/mol What is 4, the specific enthalpy of water vapor leaving the evaporator at 85.0C? = kJ/mol What is Q, the heat supplied by the evaporator? Q= kJ n, mol TC An n = 49.00 mol mixture of XEI = 0.3200 mol ethanol/mol and xwi = 0.6800 mol water/mol at T = 13.0 C enters an evaporator. A liquid and a vapor stream leave the evaporator, both at T2 = 85.0 C. The vapor product stream is composed of XE2 = 0.4590 mol ethanol/mol and Xw2 = 0.5410 mol water/mol. The liquid product stream is composed of XE3 = 0.1130 mol ethanol/mol and Xw3 = 0.8870 mol water/mol. e mol E/mol w mol W/mol Evaporator QkJ n, mol C Determine the amount of heat supplied by the evaporator by following the steps in this question. Use the given equation to describe the heat capacity of liquid ethanol 000 mol E/mol xw, mol W/mol Cp = 5.57 x 10-4T + 103.1 x 10-3 where T is in degrees Celsius and Co is in kJ/mol.C). n, mol Y, C What is n2, the moles of vapor product stream? mol E/mol tw, mol W/mol n2 = mol What is nz, the moles of liquid product stream? n3 = mol Calculate the specific enthalpy of the streams. Choose a reference state of the conditions of the incoming stream to simplify the calculations. Refer to the table for variable names. References: ethanol (liquid, 13.0C, 1 atm), water (liquid, 13.0 C, 1 atm). Substance nin (mol) Hin (kJ/mol) nout (mol) out (kJ/mol) Ethanol (1) (n)(XED) 0 (n3) (XE3) Water (1) (n)(xwi) (n3) (x3) H2 Ethanol (v) (n2) (XE2) Water (v) (n2) (Xw2) 4 0 What is the specific enthalpy of liquid ethanol leaving the evaporator at 85.0 C? 1. h = II kJ/mol What is 2, the specific enthalpy of liquid water leaving the evaporator at 85.0 C? 2 = = kJ/mol What is 13, the specific enthalpy of ethanol vapor leaving the evaporator at 85.0 C? 3 = kJ/mol What is 4, the specific enthalpy of water vapor leaving the evaporator at 85.0C? = kJ/mol What is Q, the heat supplied by the evaporator? Q= kJ
