n :r m 109 9 a Ready This test is: A two-tail test. A lower-tail test. An upper-tail test. d A closed-interval test. 101 96 114 69 87 90 111 94 103 84 109 88 122 78 94 1 ran E270TEST6 79 99 74 89 82 96 109 95 108 65 149 118 67 103 82 113 65 107 92 95 99 108 92 113 62 89 85 94 94 70 The test statistic is, |TS| = _ 1.967 ll . 8- I2 I I l E II . . Consider the following hypothesis test. Ho: ll 5 90 H1: u > 90 86 87 70 94 95 103 113 103 82 97 110 84 92 95 97 62 102 94 118 108 113 100 75 95 84 124 96 99 93 97 99 56 48 105 62 83 98 77 127 116 125 74 62 86 96 66 129 94 82 78 64 105 88 106 103 77 83 81 85 101 You obtain the following random sample to test the hypothesis in the previous question. 65 78 105 80 124 89 53 81 86 127 88 107 90 115 129 91 90 82 100 100 109 130 58 124 70 91 99 100 85 65 109 9 The test statistic is, |TS| = 110 a 1.967 111 1.639 112 1.366 113 d 1.138 114 115 116 117 118 119 120 121 122 123 10 The critical value for a 5 percent level of significance is: 124 a 1.464 125 b 1.557 126 1.656 127 1.762 128 129 130 131 132 133 134 11 The p-value for the test is, 135 a 0.0128 136 0.0256 137 0.0513 138 d 0.1026a 1.694 180 b 1.694 49 50 68 72 71 74 64 75 77 60 63 69 46 48 87 94 52 76 52 68 51 67 56 66 42 73 H1 H1 H1 H1 59 53 66 45 48 55 57 49 86 74 56 77 43 :u 60 :ua 60 :us 60 52 45 81 47 59 54 61 56 41 71 47 77 65 For the previous question, the test statistic is |TS| = Reject Ho. Conclude the average commuting time in IMA is greater than the national average. UN R l-lo. Do not conclude the average commuting time in IMA is greater than the ..-.|.:-__-'l 79 83 73 63 62 56 50 48 87 61 81 63 59 38 49 64 43 64 55 69 56 58 60 39 43 82 152 American workers spend an average of 60 minutes to and from work in a typical day. 153 You obtain the following random sample of employed adults in Indianapolis metropolitan area 154 [IMA] to test the hypothesis below: 58 47 68 84 55 77 79 60 75 34 75 60 61 79 34 77 67 69 49 33 67 79 65 80 66 81 61 70 56 43 73 53 65 34 56 46 52 68 97 169 ls there enough evidence, at a = 0.05, to conclude that the average commuting time in IMA is greater 170 than the national average? 171 13 To perform a hypothesis test, the null and alternative hypotheses for this test are: a Ho: u 2 60 173 b Ho: u s 60 c Ho: u 60 14 For the previous question, the test statistic is |TS| = a 1.694 Reject Ho. Conclude the average commuting time in IMA is greater than the national average. b 1.694 UN R 110. Do not conclude the average commuting time in IMA is greater than the national average. c 1.411 Reject Ho. Conclude the average commuting time in IMA is greater than the national average. d 1.411 DNR Ho. Do not conclude the average commuting time in IMA is greater than the national average. 15 In the previous question the p-value = a 0.0804 198 b 0.0619 c 0.0476 200 {1 0.0366 16 The expected ll of bottles of a beverage lled in a bottling plant is 750 milliliters [ml]. You obtain the following random sample of lled bottles. 748.14 750.04 750.74 749.39 750.44 749.85 749.86 749.38 750.44 747.59 749.2 749.5 Does the sample provide signicant evidence that the mean ll is different from the expected ll? Compute the test statistic [TS] and the critical value at the 5% level of TS CV 1.692 1.431 Conclude the mean ll is different from the expected ll. 1.692 2.201 Do not conclude the mean ll is different from the expected ll. 2.369 1.860 Do not conclude the mean ll is different from the expected ll. 2.369 2.201 Conclude the mean ll is different from the expected ll. mac's: 230 231 Questions 17 and 20 are related Sample data 232 The national obesity statistics indicates that 41 percent of American adults is obese. 0 o H O O O O OO 233 To test the hypothesis that the percentage of Indiana adults who are obese is greater than the HOO 234 national rate of obesity the following random sample is obtained. 235 In the binary sample data shown "1" indicates that the person is obese and "0" not obese. 236 17 The fraction of the persons in the sample who are obese is p = OHOH 237 0.467 OHHOOH DOHOOOO DOOOO HO OOH O OHHOOHHHH 238 0.459 JOOHHHHHOR 239 0.450 OHHOO DOO HOHO 240 d 0.442 PHHOOOOHOHOHO DOHOO HOO OOH OH 241 242 OOHOOH OH OO H OHHHHH PHOOOHHOH 243 HHHHH 244 HHO OHOOHHOHHOOHH H HOHOHO 245 HO OOH HOO O O H O H H H H O H OOHOOH 246 HOON OOOH H OO OO OOOH HOH H OPP 247 18 The standard error of the sample proportion is 248 0.0155 OHHHHHOOOOOH H H O H H H O H H O O H O O H H H H O O O H H O O H HHHH OH OH O O O H H H O H O O H O H O O H O O O O O O H H H O OHH HOOOO 249 0.0165 O H H O O H O O H O H H H O O H O O H H O O H H O H OHHHOPP O OOOH OHH H OO OO OO H H OO H OH H O O OHHOH OHH H OO OO H OH OOH H OOHH OH OH HOOOHO DOOHHHH 250 0.0176 DO OHOHHOHO OHHO 251 O O H HOO HOO H H O O H H H O O H HOO HOO O HOO 0.0187 252 O POOH 253 OH 254 OHH 255 DOHO OHHHHOC 256 OOHO 257 OHH HOHOH 258 259 19 Does the sample provide significant evidence that the obesity rate in Indiana is OHHOHO 260 higher than the national rate? State the null and alternative hypotheses: OOOHHOH 261 Ho: Tt S 0.41 H1: It > 0.41 OOH OHH OOOHHA a OHHOOK OH OHOH OHOH DOOHH 262 Ho: It > 0.41 H1: It S 0.41 HOOOHO OO 263 Ho: Tt 2 0.41 H1: It