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Name: Beat-Down Performance Task 20 Well you can tell by the way I use my walk I'm a woman's man no time to talk 000
Name: Beat-Down Performance Task 20 Well you can tell by the way I use my walk I'm a woman's man no time to talk 000 14 COO 3 3 Well you can tell by the way I use my walk I'm a woman's man 10 time to talk You are to choose a song that has a tempo between 60 and 140 BPM (beats per minute). It is up to you to determine the beats per minute of the song. Either e-mail the song to your teacher in advance of this activity, or bring the song on a music player or phone. Song Title: Love Artist: Kiesha Cole BPM: 117 (a) Calculate the number of seconds for two beats of the song. This will be the period you use for parts (b) and (e). No. of seconds = 6018 PM No. seconds for two beats = (60 1 1 1 7) x 2 ( 6 0 / 1 1 7 7 x 2 = 1. 6256 seconds b) You are given a pendulum apparatus with an adjustable length. What length must the pendulum have so that the pendulum swings back and forth in rhythm with the song? One "back" or "forth" motion would one beat. Show and explain each step below. T= 2A VS 1. 0256 = 271 40 0. 067 = 4 Time(f) Draw graphs of the motion of the mass oscillating on the spring. Pay close attention to making your graphs have the correct vertical maxima and minima and horizontal crossing points, as well as the correct shape. Assume that the position y = 0 is the position where the spring is not stretched, that the mass is pulled down 5 cm and released at time t = 0, that upward is the positive direction, and that potential energy is zero at the spring-mass oscillator's equilibrium position.(f) Draw graphs of the motion of the mass oscillating on the spring. Pay close attention to making your graphs have the correct vertical maxima and minima and horizontal crossing points, as well as the correct shape. Assume that the position y = 0 is the position where the spring is not stretched, that the mass is pulled down 5 cm and released at time t = 0, that upward is the positive direction, and that potential energy is zero at the spring-mass oscillator's equilibrium position
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