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Name Date Partners Theoretical lab- GAUSS' LAW Purpose: Theoretical study of Gauss' law. Equipment: This is a theoretical lab so your equipment is pencil, paper,

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Name Date Partners Theoretical lab- GAUSS' LAW Purpose: Theoretical study of Gauss' law. Equipment: This is a theoretical lab so your equipment is pencil, paper, and textbook. When drawing field line pattern around charge distributions we use in general three different rules: (a) Field lines start at positive charges or in infinity and end at negative charges or in infinity. (b) Field lines never cross each other. Crossing field line would mean that at the position of the crossing field lines the direction of the electric field is no longer unambiguous determined (note that the electric field direction is tangent to the field lines). (c) The field line density is linear proportional to the electric field. So the electric field is larger in areas with a lot of field lines. Also review the lecture where we relate field lines and the magnitude of the electric field On all questions, work together as a group. 1. The statement of Gauss' Law: (a) in words: The electric flux through a closed surface is equal to the total charge enclosed by the surface divided by zo'. (b) in symbols: E . dA = Pclosed surface 2. The next few questions involve point charges. (a) Draw the electric field lines in the vicinity of a positive charge to. . + 0 Eo = 8.85 x 10-12 C2/N.m2 Thanks to University of Virginia PhysicsGauss' Law (b) Do the same for a negative charge -Q. . - 0 (c) Do the same for a positive charge of +2Q. As the electric field around the charge will be twice as large as the electric field around a charge of +Q, the field line density will have to be twice as large. Make sure that you use twice as many field lines as for the field line pattern of problem 1(a). (d) Comment whether or not all field line rules provided above are obeyed. 3. Consider a "Gaussian sphere", outside of which a charge +Q lies. Remember, a Gaussian surface is just a mathematical construct to help us calculate electric fields. Nothing is actually there to interfere with any electric charges or electric fields. Thanks to University of Virginia Physics DepartmentGauss' Law + 0 (a) Draw several electric field lines from +0, but only ones that intersect the sphere. (For this question, omit field lines that don't intersect the sphere. This is to keep the drawing looking neat.) (b) How much charge is enclosed by the sphere? Applying Gauss' Law, what is the total electric field flux through the sphere? Justify your answer. (c) Looking back at your drawing, field lines impinge on the spherical surface from the outside heading inward (this is defined as negative flux) and eventually impinge on another part of the surface from the inside heading outward (positive flux). Does it seem reasonable that the total flux through the sphere is exactly zero? If we count the field lines leaving the sphere as positive and the field lines entering the sphere as negative, is the net number of field lines entering or leaving the sphere is zero? Thanks to University of Virginia Physics DepartmentGauss' Law (d) Suppose we replaced the sphere with a cube. Would the total flux still be zero? . + Q Note that it would be difficult to actually calculate the electric field flux through these surfaces (although you could certainly do it) because the electric field strength and angle of intersection vary over the surface. Applying Gauss' Law, however, made it easy. 4. Now consider a Gaussian sphere centered on to. (a) Draw some electric field lines. Make them long enough to intersect the sphere. (b) Is the total electric field flux through the sphere positive or negative? Does this make sense, considering the charge enclosed? Discuss. Thanks to University of Virginia Physics DepartmentGauss' Law (c) In symbols, what is the total flux through the sphere? [Use equation in step 1(b).] Notice that in this case the electric field lines intersect the sphere perpendicular to its surface and that the electric field strength is uniform over the surface. (d) How do we know that the electric field strength does not vary over the surface? (e) Because of the simplifying conditions discussed in part (d), we can apply Gauss' Law to find the electric field due to +0. Find the electric field for a point charge +Q. (Recall that the surface area of a sphere is 4T1/2.) (f) Graph E (the magnitude of E) versus r, using the axes given. [Both axes have linear scales.] (g) If we had picked a cube as our Gaussian surface instead of a sphere, would it still have been easy to determine the total flux through the surface? What about calculating the electric field strength? Explain. Thanks to University of Virginia Physics DepartmentGauss' Law 5. The previous problem was mathematically fairly simple. Here's another problem requiring Gauss' Law, but this time you will have to do a bit of integration. NOTE: Keep your results in symbolic form and only substitute in numbers when asked for a numerical result. Also, pay careful attention to the distinction between the radius of the sphere, R, and the distance, r, from the center of the s uhere at which on are evaluatin E. Consider a small sphere (an actual sphere, not a Gaussian surface) of radius R = 0.] m that is charged throughout its interior, but not uniformly so. The charge density isp=Br , where r is the distance from the center, and B = 10'4 C/m4 is a constant. Of course, for r greater than R, the charge density is zero. R=0.lm (a) What does the charge density converge to as you approach the center of the sphere? Does it increase or decrease as we move toward the surface? Explain. (b) What does E converge to as you approach the center of the sphere? How do you know? How does this compare to the E of a point charge? [Hint: Consider the symmetry of the problem] (c) Apply Gauss' Law to nd an expression forE when r is less than R. [Hint: the volume of a thin spherical shell of radius r and thickness air is d V =4nr ai'r2 .] Thanks to University of Virginia Physics Dcpanmenl Gauss' Law (d) What is E at r = 0.05 m? [Your answer should be in WC] (e) Apply Gauss' Law to find an expression for E when r is greater than R. (D What is E at r = 5.0 m? (g) Make an approximate graph of E versus r on the axes shown below: 0 0.1m (h) Determine the total charge inside the sphere. Outside the sphere, how does E compare to E of a point charge of that magnitude? Verify for r = 5.0 m. (i) On your graph in part (g) above, use a dotted line to represent the electric eld if the sphere shrank to a point charge but still contained the same total charge. Thanks to University ofVirginia Physics Department

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