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NASA launches a rocket at t=0t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=4.9t2+73t+199h(t)=-4.9t2+73t+199. Assuming that the

NASA launches a rocket at t=0t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=4.9t2+73t+199h(t)=-4.9t2+73t+199. Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? The rocket splashes down after seconds. How high above sea-level does the rocket get at its peak? The rocket peaks at meters above sea-level.Check AnswerQuestion 5

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