NBC claims that viewers spend a daily average of 139.3 minutes watching their content. An advertiser wants to verify this and conducts a poll of 37 random viewers who claim to watch NBC. The poll showed that this group spends a daily average of 137.5 minutes watching NBC with a standard deviation of 2.8 minutes. Use a 0.05 significance level to test the claim that the daily average amount of time NBC viewers watch NBC is different from 139.3 minutes, the average amount claimed by NBC.. Claim: Select an answer u 139.3 p 139.3 p < 139.3 u 139.3 u > 139.3 p 139.3 p > 139.3 p = 139.3 p 139.3 u = 139.3 u < 139.3 u 139.3 Incorrect which corresponds to Select an answer H0: u 139.3 H1: u < 139.3 H0: u 139.3 H1: u 139.3 H1: u > 139.3 H0: p 139.3 H0: u = 139.3 Correct Opposite: Select an answer u = 139.3 u 139.3 u > 139.3 u 139.3 p 139.3 u < 139.3 p < 139.3 p = 139.3 u 139.3 p 139.3 p 139.3 p > 139.3 Correct which corresponds to Select an answer H1: u 139.3 H1: u > 139.3 H0: u = 139.3 H0: p 139.3 H0: u 139.3 H1: u < 139.3 H0: u 139.3 Correct The test is: Select an answer two-tailed left-tailed right-tailed Correct The test statistic is: Correct (to 3 decimals) The Critical Value is: Correct (to 3 decimals) Based on this we: Select an answer Fail to reject the null hypothesis Reject the null hypothesis Correct Conclusion There Select an answer does does not Correct appear to be enough evidence to support the claim that the daily average amount of time NBC viewers watch NBC is different from 139.3 minutes, the average amount claimed by NBC..Question HelpQuestion 9:

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