NBC claims that viewers spend a daily average of 150.2 minutes watching their content. An advertiser wants to verify this and conducts a poll of 36 random viewers who claim to watch NBC. The poll showed that this group spends a daily average of 134.3 minutes watching NBC with a standard deviation of 42.5 minutes. Use a 0.02 significance level to test the claim that the daily average amount of time NBC viewers watch NBC is equal to 150.2 minutes, the average amount claimed by NBC.. Claim: Select an answer p = 150.2 u = 150.2 p 150.2 p 150.2 u 150.2 p < 150.2 u < 150.2 u 150.2 u > 150.2 p > 150.2 u 150.2 p 150.2 which corresponds to Select an answer H1: u 150.2 H0: p 150.2 H1: u < 150.2 H0: u = 150.2 H0: u 150.2 H0: u 150.2 H1: u > 150.2 Opposite: Select an answer u 150.2 p < 150.2 p = 150.2 u 150.2 u > 150.2 u = 150.2 p 150.2 u 150.2 p > 150.2 p 150.2 p 150.2 u < 150.2 which corresponds to Select an answer H1: u 150.2 H0: p 150.2 H0: u 150.2 H1: u < 150.2 H0: u = 150.2 H0: u 150.2 H1: u > 150.2 The test is: Select an answer two-tailed left-tailed right-tailed The test statistic is: (to 3 decimals) The Critical Value is: (to 3 decimals) Based on this we: Select an answer Reject the null hypothesis Fail to reject the null hypothesis Conclusion There Select an answer does does not appear to be enough evidence to support the claim that the daily average amount of time NBC viewers watch NBC is equal to 150.2 minutes, the average amount claimed by NBC..