Need a step by step explanation of this. Answer is 346.4. Formulas have to come from the sheet.

A solid pulley of mass 21.3 kg and radius 1.413 m has 2 ropes pulling on it with no angle (in other words, the angle is exactly 90 degrees to the radius), one to spin in counterclockwise and the other to spin in clockwise. The counterclockwise rope has a tension of 62 N. The pulley has an angular acceleration of 18.9 rad/s². What is the magnitude of the other rope on the pulley Round to 1 decimal.

Final Formula Sheet. Nothing can be written on this paper before the test. Q = mcAT Q = ml Ly = 2260000 - Ax Av Xf = *, tut kg V= A At At = = 20AT4 1 cal = 4.184 / At Ly = 333000 Of = Vo + at v; = v; + 2a(X - X.) kg f= Xitvattaxt? Cice = 2010 1 atm = 101300 Pa = P. g = 9.8 m/ 2 a = gsin(0) gt2 Csteam = 1996 Kg K Kg K 2 PoVo = PFVF KAAT a' + b= = c3 2.54 cm = 1 inch 1609 m = 1 mi At L Opp Adj Opp sin 8 = Hyp coS 0 = 7 Hyp tan 8 = - Adj Patpvi + pgh, = P. + - pvi + pgh, GMm F =. 1- = 2.24 mph 2n rad = 360 degrees = 1 rev Axis 72 Axis GM 100 cm = 1 m = 3.28 ft Hoop about Annular cylinder ap =. 9 - 72 (or ring) about r cylinder axis cylinder axis A = 17-2 C = 2ur G = 6.67x10-11 Nm3/kg EF = ma Fa = mg f = un 1 = MR2 1 = M(R + R) s = re v = wr a = ra Wf = wo + at w; = w8 + 2a(0, - 0;) Axis Axis Solid cylinder Solid cylinder w = 2nf Of = 0; + wt (or disk) about (or disk) about WE At cylinder axis central diameter v = 2arf Aw T = 7 a = - 1 = MR2 1- MR + Me At 2 Et = la T = rF sin O 1 = > mr2 Axis Axis Thin rod about Thin rod about axis through axis through one F YAL Impulse = FAt Impulse = mvf - mv. center 1. to end 1 to length A= L length P; = PF Li = L p = mv 1 = Mez L = Iw PE, = mgh 12 3 Axis Axis KE = =mv- PEsp = =kx2 Eth = fd Solid sphere Thin 2R W = AKE 28 spherical shell KErot = = Iw= W = Fd cos 0 about any diameter about any Eth = Q +W Eth = W - APE TEbefore = TEafter diameter P = Fv F = KAL 1 hp = 746 W 1 = 2MR 1 = 2MR 5 P-VF POV. PV = nRT W = P(V, - V.) 3 If Axis To Axis Slab about m K= = 1.38x10-23 - P = 77 R = 8.314- 1 axis through *mol K Hoop about center F 1 m3 = 1000 L FB = pVg R any diameter P A P = P. + pgd AL = aLAT P = + 1 = MR2 1= M (a2 + 62) 5 C =K - 273.15 AV = BV,AT 12 (F - 32) Cwater = 4184 4_ Kg K V= Smy SORT = , NKST = U 1mol = 6.02x1023 AV Q = At = Av AV1 = A,V2