need answers for these questions

question1:

question 2: Convert following code in Listing into its equivalent RISC-V assembly 1. int a = 5 ; 2. int b = 33; 3. int c = 55; 4. int d = 6 5. int e = ( ( ( ad )+(ba ) )+d )c ;

The following example will help us to understand the basics of registers and Risc V It is the compiler's job to associate program variables with registers. Take, for instance, the assignment statement from our earlier example: f=(g+h)(i+j); word A natural unit of access in a computer, usually a group of 32 bits. doubleword Another natural unit of access in a computer, usually a group of 64 bits; corresponds to the size of a register in the RISC-V architecture. EXAMPLE 68 Chapter 2 Instructions: Language of the Computer The variables f,g,h,i, and j are assigned to the registers x19,x20,x21,x22, and x23, respectively. What is the compiled RISC-V code? The compiled program is very similar to the prior example, except we replace the variables with the register names mentioned above plus two temporary registers, x5 and x6, which correspond to the temporary variables above: add 5,20,x21// register x5 contains g+h add x6,x22,x23// register x6 contains i+j sub x19,x5,x6//f gets x5x6, which is (g+h)(i+j) Convert the following statement to RISC V . You can use the same registers as given in Example 1 - b=0+0; - a=b+32; - c=a+b; - d=c5; e=a+b+c+d