Need d-e

n 5. A 2018 survey conducted by NBC News of 1895 random adults aged 18-34 asked whether they currently had more debt than savings and found 62% said yes. Note that there are 76.1 million adults aged 18-34 in the U.S. (Source and Source) P N a. Verify that the conditions are met in order to construct a confidence interval for p. Random - Independent Random yes given Normal Independent 8 12 0. 05 18954 0.05 ( 76. 1 millon) Normals np9 2 10 1895 (0. 62 ) ( 1 - 0. 62 ) = 446,462 yes 446.462210 ( .38 ) x = ? b. Calculate how many in the sample said they had more debt than savings. (Round to whole number) P =x 1895 X= 1 175 people 0. 62=* 1895 = 1174.9 (0. 995) n= 1895 c. Construct a 99.5% confidence interval for p. (Give 5 decimal places; Show formula, substitution, and result.) use so formula Formula tell Pa Substitution Substitution P+ (2.80*) ( 0. 62 ) (0.38 ) 10 . 03124 Result 1845 -use se Results d. Interpret the interval in the context of the situation. pana script We can say we are 99.5 confident that the e. A journalist claims that more than 60% of adults aged 18-34 in the U.S. have more debt than savings. Does your interval support or contradict their claim? Explain. support, since Contradict, since 60% Support, since Contradict, since 60% 60% is above is above 60% is within is within the interval the interval the interval the interval