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Need help Consider the following. h (x ) = exz - 4 Find h'(x). h' ( x ) = 2xox- - 4 Solve h '(x)

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Consider the following. h (x ) = exz - 4 Find h'(x). h' ( x ) = 2xox- - 4 Solve h '(x) = 0 for x. X Find h(0), h(-2), and h(2). h(0) = 0 X h(-2) -4 X h(2) 4 X Find the absolute extrema of the function h(x) = ex - 4 on [-2, 2] Absolute maximum value: at x = + Absolute minimum value: at X =

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