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Need help Equations Consecration of Momentum dA M = V = At TA 1 13 m = V. = 4d At P= Momentum PA=MA *

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Equations Consecration of Momentum dA M = V = At TA 1 13 m = V. = 4d At P= Momentum PA=MA * VA PB = MB * VB Then if Law true PA - PB = 0 3 PA - P3 = N Ave Pa PA + P13 Avep Tria Mass Vel P AP= PA - P 13 y 501 A 1 13 X 498 6022.51 501 204 . 49 A 3 498+ 50 8.42 501 A 13 494 +100 #5 . 43 501 .47 4 B 498+ 120 .35 A 501 . 5 5 B 498 + 150 . 36 A 501+ 50 . 45 - 6 498+ 1001 36

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