Need help in solving and understanding the calculator function that is used.

2. A consumer advocacy group randomly samples and weighs 30 bags of wood pellets from a manufacturer that packages thousands of them daily. The mean weight of the sample is 19.9 pounds and the standard deviation is 0.105 pounds. The group wants to construct a 95% confidence interval to estimate the mean weight of all bags of wood pellets from this manufacturer.

A) Notice this problem does not provide the population mean and population standard deviation. How does that change the problem? (Hint: Are we still using the normal distribution when we don't know the population parameters?)

B) What are the degrees of freedom for this sample?

D) What is the multiplier used to calculate the margin of error? DF 90% 95% 98% 99% 28 1.701 2.048 2.467 2.763 29 1.699 2.045 2.462 2.756 30 1.697 2.042 2.457 2.750 34 1.691 2.032 2.441 2.728 E) Calculate the margin of error for the 95% confidence interval. Round answer to 3 decimal places.

F) Use the margin of error you found in E to create a 95% confidence interval. Round values of the interval to 2 decimal places.

G) Is there evidence to reject the manufacturer's claim that the bags of wood pellets are 20 pounds? Explain.