Question: Need help po. Please provide solutions and explanations. Thank you. 1. A proton moving horizontally at 3-7 x 105 m/s enters a uniform magnetic field

Need help po. Please provide solutions and explanations. Thank you.

Need help po. Please provide solutions and explanations. Thank you. 1. Aproton moving horizontally at 3-7 x 105 m/s enters a uniform magneticfield of 0.086 T directed upward at 350 with the horizontal. Findthe magnitude of the magnetic force acting on the proton? 2. A

1. A proton moving horizontally at 3-7 x 105 m/s enters a uniform magnetic field of 0.086 T directed upward at 350 with the horizontal. Find the magnitude of the magnetic force acting on the proton? 2. A proton moves through a magnetic field of magnitude 4.5 T at a speed of 7.08 x 100 m/s perpendicular to the field. Find the a. centripetal acceleration b. radius of the circular path of the proton A. DE VERO3. A 1.5 nC particle with an initial velocity of 4.75 x 106 m/s along the positive x - axis enters a region of uniform magnetic field and electric field. The magnetic field is 3.25 T along the positive y - axis. Calculate the magnitude and direction of the electric field if the particle passes the region undeflected. 4. A 135 m long transmission wire is stretched between two vertical posts. It carries of a current of 45-5 A and experiences a force of 0.45 N due to Earth's magnetic field. What is the value of Earth's magnetic field at the location of the wire 80 with it?1. A copper wire is 2.50 m long and has a diameter of 2.5 mm. How much current will it draw when connected to 3.5 V source? 2. An electromotive force of a cell is 3.85 V and is connected to a load of 4-25 0, the voltage drops to 2.0 V. Find the current and internal resistance of the cell. 3. A CFL or compact fluorescent lamp uses less energy that its equivalent incandescent bulb. How much will a person save of he uses a 30 W CFL instead of 100 W incandescent lamp for 7 hr in 30 days? Electricity is priced at 9.55 php / kW.hr4. Find the equivalent resistance of the combination of resistors shown below: R2 - 3.5 52 RX - 2.5 52 R - 5.0 2 9.252 RA = 24.052 source: Silverio, A.A et al (2017), Exploring Life Through Science Series: General Physics 2

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