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Need help with review. 15. Adding two two's complement numbers in binary. 10101 and 10010 for w-5, gives (a)16, (b)48, (c)-15, (d)-16, (e) none of
Need help with review.
15. Adding two two's complement numbers in binary. 10101 and 10010 for w-5, gives (a)16, (b)48, (c)-15, (d)-16, (e) none of the above 16. Multiplying two two's complement numbers in binary. x-10000 andy-10101 for w-5, gives truncated binary (a)10101,(b)10001 (c)10110, (d)10000 (e) none of the above 17. Floating point for binary 0 01111110 00000000000000000000000 is, where the most significant bit 0 is sign bit, 01111110 is exponent, and the rest is significand (a)126.0, (b)0.25, (c)0.5, (d)0.75, (e) none of the above 18. Float 1.0 in binary is: (a)0 01111110 00000000000000000000000 (b)0 01111110 10000000000000000000000 (c)0 01111111 00000000000000000000000 (d)0 01111111 10000000000000000000000 (e) none of the above 19. Multiplying integer variable x by a constant factor K can be rewritten in a set of operations in shifts and additions/subtractions. Shifting a number regardless of the nubmer of bits shifted is a single opera- tion. The minimum number of operations in shifts and additions (subtractions) for x * 63 is (b)2, (c)3, (d)4. (e) none of the above 20. Rounding 2 5/8 to the nearest quarter (2 bits to the right of the binary point), according to the round-to- even rule results in (a)10.01, (b)10.10, (c)10.11, (d)11.00 (e) none of the aboveStep by Step Solution
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