Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Need help with screenshots 1 through 10. I only need answers wherever the blank space is within the screenshot. So, please look directly at the

image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed

Need help with screenshots 1 through 10. I only need answers wherever the blank space is within the screenshot. So, please look directly at the screenshot, as they provide all the information you need. If there is anything else you would like, please let me know by commenting. Thank you a lot.

image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed
The accompanying data represent the weights (in grams) of a simple random sample of 48 M&M plain candies. Determine the shape of the distribution of weights of M&Ms by drawing a frequency histogram. Find the mean and median. Which measure of central tendency better describes the weight of a plain M&M? Click the icon to view the candy weight data. Draw a frequency histogram. Choose the correct graph below. Weight of Plain M and Ms Weight of Plain M and Ms OA 123 B Frequency Weight (grams) Of 0.78 0.84 0.9 0.96 Weight (grams) Weight of Plain M and Ms Q 123 - X O C. Frequenc 6 O D. Candy Weights 0.84 0.9 0.96 Weight (grams) 0.88 0.82 0.90 0.84 0.84 0.91 0.94 0.86 0.86 0.86 0.88 The mean is x = 0.874 gram(s). 0.87 0.89 0.91 0.86 0.87 0.93 (Round to three decimal places as needed.) 0.88 0.83 0.95 0.87 0.93 0.91 0.85 0.91 0.91 0.86 0.89 0.87 The median is M = gram(s) 0.84 0.88 0.88 0.89 0.79 0.82 (Round to three decimal places as needed.) 0.83 0.90 0.88 0.84 0.93 0.81 0.90 0.92 0.85 0.84 0.84 0.86 Print Done Help Me Solve This View an Example Get More Help - Clear All Check Answer CVP Excel projexIsx ~ Show All X2 Each of the following three data sets represents the IQ scores of a random sample of adults. IQ scores are known to have a mean and median of 100. For each data set, compute the mean and median. Full data set What is the mean of the sample of size 5? Sample of Size 5 108 103 92 109 103 10 Sample of Size 12 (Type an integer or decimal rounded to one decimal place as needed.) 108 103 92 109 103 110 106 11 113 What is the mean of the sample of size 12? 114 113 95 Sample of Size 30 106.4 108 103 92 109 103 113 (Type an integer or decimal rounded to one decimal place as needed.) 110 106 111 114 113 95 What is the mean of the sample of size 30? 107 91 110 103 100 103 118 113 99 92 110 97 110 105.5 101 110 104 109 111 (Type an integer or decimal rounded to one decimal place as needed.) What is the median of the sample of size 5? 103 (Type an integer or decimal rounded to one decimal place as needed.) What is the median of the sample of size 12? 108.5 (Type an integer or decimal rounded to one decimal place as needed.) What is the median of the sample of size 30? 107.5 (Type an integer or decimal rounded to one decimal place as needed.) For each data set recalculate the mean and median, assuming that the individual whose IQ is 108 is accidently recorded as 180. What is the mean of the new sample of size 5? (Type an integer or decimal rounded to one decimal place as needed.) "what is the new sample of size 12, 30?" Help Me Solve This View an Example Get More Help - Clear All Check Answer CVP Excel projex..xisx Show All X3 The tollowing data represent exam scores in a statistics class taught using traditional lecture and a class taught using a "ipped" classroom. Complete parts (a) through (c) below. Traditional 71.6 69.4 80.4 67.3 84.5 79.3 56.6 Eh 81.2 80.1 71.5 63.6 70.2 58.9 Fllpped 76.3 71.1 63.2 73.1 77.9 90.9 78.6 76.4 82.5 69.6 90.6 77.7 76.7 (3) Which course has more dispersion in exam scores using the range as the measure of dispersion? The traditional course has a range of 27.9 . while the 'flipped' course has a range of 27.7 . The traditional course has more dispersion. (Type integers or decimals. Do not round.) (h) Which course has more dispersion in exam scores using the sample standard deviation as the measure of dispersion? The traditional course has a standard deviation of 3.860 . while the "ipped" course has a standard deviation of 7.678 . The traditional course has more dispersion. (Round in three decimal places as needed.) (c) Suppose the score of 58.9 in the traditional course was incorrectly recorded as 589. How does this affect the range? The range is now . (Type an integer or a decimal. Do not round.) Help Me Solve This View an Example Get More Help a Clear All 4 In December 2018, the average price of regular unleaded gasoline excluding taxes in the United States was $3.06 per gallon.Assume that the standard deviation price per gallon is $0.09 per gallon and use Chebyshev's Inequality to answer the following. (a) What minimum percentage of gasoline stations had prices within 2 standard deviations of the mean? (b) What minimum percentage of gasoline stations had prices within 2.5 standard deviations of the mean? What are the gasoline prices that are within 2.5 standard deviations of the mean? (c) What is the minimum percentage of gasoline stations that had prices between $2.70 and $3.42? (a) At least 75 \"In of gasoline stations had prices within 2 standard deviations ofthe mean. (Round to two decimal places as needed.) (b) At least 84 \"A of gasoline stations had prices within 2.5 standard deviations of the mean. (Round to two decimal places as needed.) The gasoline prices that are within 2.5 standard deviations ofthe mean are $ to $ (Type integers or decimals. Do not round. Use ascending order.) Help Me Solve This View an Example Get More Help a Clear All 5 The data set below on the left represents the annual rate of return (in percent) of eight randomly sampled bond mutual funds. and the data set (a) Determine the mean and standard deviation of each data set. below on the right represents the annual rate of return (in percent) at eight randomly sampled stock mutual funds. Use the information in the table below to complete parts (a) through (d). Then complete part (9). The mean of the data set for bond mutual funds is 2.175 . (Type an integer or decimal rounded to three decimal places as needed.) Bond mutual Stock mutual D funds fund! The standard deviation of the data setfor band mutual funds is 0,669 . 30 1-5 9-2 7-4 (Type an integer or decimal rounded to three decimal places as needed) 1.7 3.2 8.9 7.2 2,2 2.5 8.2 70 The mean of the data set for stock mutual funds is . 1.4 \"3 7.9 6.7 (Type an integer or decimal rounded to three decimal places as needed.) Help Me Solve This View an Example Get More Help a Clear All 6 Complete parts (a) through (h) for the data below. y 3 8 8 11 13 (a) By hand, draw a scatter diagram treating x as the explanatory variable and y as the response variable. Choose the correct scatter diagram below. O A B. O C. O D 20- 10- O 10 (b) Find the equation of the line containing the points (2,3) and (7, 13). y= 2x + (-1) (Type integers or simplified fractions.) (c) Graph the line found in part (b) on the scatter diagram. Choose the correct graph below. OA VB. OC OD 20- 20- 1 x 10 (d) By hand, determine the least-squares regression line. y= 1.977 x+ - 0.698 (Round to three decimal places as needed.) (e) Graph the least-squares regression line on the scatter diagram. Choose the correct graph below. OA OB C. D 10- 20- Help Me Solve This View an Example Get More Help - Clear All Check Answer CVP Excel projexisx Show All X7 Complete parts (a) through (h) for the data below. 20 40 y 100 95 50 90 82 60 70 (a) By hand, draw a scatter diagram treating x as the explanatory variable and y as the response variable. Choose the correct scatter diagram below. O A B. C. 100- 70- 70 10% (b) Find the equation of the line containing the points (30,95) and (60,70). y= - 6 X+ (120) (Type integers or simplified fractions.) (c) Graph the line found in part (b) on the scatter diagram. Choose the correct graph below. OA OB &C. Q OD 100- 100- 10 of 70 70 (d) By hand, determine the least-squares regression line. y= - 0.73 x+ 116.6) (Round to three decimal places as needed.) (e) Graph the least-squares regression line on the scatter diagram. Choose the correct graph below. OA B. O C. 100-T O D. 100-1 701 70- 10 70 70 Help Me Solve This View an Example Get More Help - Clear All Check Answer CVP Excel projex.xisx Show All X8 The data below represent commute times (in minutes) and scores on a well-being survey. Complete parts (a) through (d) below. Commute Time (minutes), x 5 20 30 35 60 72 105 Well-Being Index Score, y 69.2 67.9 67.0 66.8 65.4 65.4 62.9 . . . . . (a) Find the least-squares regression line treating the commute time, x, as the explanatory variable and the index score, y, as the response variable. y= - 0.058 x + ( 69.103 ) (Round to three decimal places as needed.) (b) Interpret the slope and y-intercept, if appropriate First interpret the slope. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. For every unit increase in index score, the commute time falls by , on average. Round to three decimal places as needed.) O B. For every unit increase in commute time, the index score falls by , on average. Round to three decimal places as needed.) O C. For an index score of zero, the commute time is predicted to be minutes. (Round to three decimal places as needed.) O D. For a commute time of zero minutes, the index score is predicted to be (Round to three decimal places as needed.) O E. It is not appropriate to interpret the slope. Help Me Solve This View an Example Get More Help - Clear All Check Answer CVP Excel projexIsx ~ Show All XOne of the biggest factors in determining the value of a home is the square footage. The accompanying data represent the square footage and selling price (in thousands of dollars) for a random sample of homes for sale in a certain region. Complete parts (a) through (h) below. Click the icon to view the housing data. (a) Which variable is the explanatory variable? Square Footage Selling Price -X (b) Draw a scatter diagram of the data. Choose the correct scatter diagram below. Data Table OA B. C. Square Footage, X Selling Price ($000s), y 4500 1500- 2239 385.6 3169 373.4 1112 187.4 2050 349.7 X 3188 1000 632.8 150 1000 4500 1000 2892 389.3 4141 631.8 (c) Determine the linear correlation coefficient between square footage and asking price. 2166 369.9 2621 426.9 r= 0.903 1778 309.1 (Round to three decimal places as needed.) 1790 271.6 (d) Is there a linear relation between square footage and asking price? 3763 682.3 No Yes Print Done (e) Find the least-squares regression line treating square footage as the explanatory variable. y=x+(0) (Round the slope to three decimal places as needed. Round the intercept to one decimal place as needed.) Help Me Solve This View an Example Get More Help - Clear All Check Answer CVP Excel projexIsx Show All X10 Because colas tend to replace healthier beverages and colas contain caffeine and phosphoric acid, researchers wanted to know whether cola consumption is associated with lower bone mineral density in women. The accompanying data lists the typical number of cans of cola consumed in a week and the femoral neck bone mineral density for a sample of 15 women. Complete parts (a) through (f) below. Click the icon to view the women's data. (a) Find the least-squares regression line treating cola consumption per week as the explanatory variable. y= - 0.0231 x + ( 0.9002 ) (Round to four decimal places as needed.) - X (b) Interpret the slope. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. Colas per Week and Bone Density A. For every unit increase in bone density, the number of colas decreases by , on average. Round to four decimal places as needed.) colas per week Bone Mineral Density (g/cm3) O B. For 0 colas consumed in a week, the bone density is predicted to be g/ cm3. 0.906 (Round to four decimal places as needed. 0.873 0.885 O C. For every additional cola consumed per week, the bone density decreases by g/ cm, on average. 0.875 (Round to four decimal places as needed.) 0.862 D. For a bone density of 0 g / cm, the number of colas consumed is predicted to be . 0.845 (Round to four decimal places as needed.) 0.820 O E. It is not appropriate to interpret the slope. 0.829 0.783 V V V O CI CI CI W W N N - 0.788 0.784 0.760 0.735 0.744 0.74 Print Done Help Me Solve This View an Example Get More Help - Clear All Check Answer CVP Excel projexIsx ~ Show All X

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Algebra And Trigonometry Enhanced With Graphing Utilities (Subscription)

Authors: Michael Sullivan, Michael Sullivan III

7th Edition

0134273842, 9780134273846

More Books

Students also viewed these Mathematics questions