Need help with screenshots one through eleven (1-11). All information necessary in order to solve each individual problem(s) can be found below. Screenshot three (3) includes two photographs in total, as the graphs would not fit in one parcel. ALL screenshots are one-parted, NONE include multiple parts. Please only answer where needed (the blanks, save time for yourself). I ALSO DO NOT NEED ANY EXPLANATIONS! ONLY SOLUTIONS. This is for your convenience! Thank you.

A survey of 2287 adults in a certain large country aged 18 and older conducted by a reputable polling organization found that 422 have donated blood in the past two years. Complete parts (a) through (c) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Obtain a point estimate for the population proportion of adults in the country aged 18 and older who have donated blood in the past two years. p = 0.185 (Round to three decimal places as needed.) (b) Verify that the requirements for constructing a confidence interval about p are satisfied. The sample is stated to be a simple random sample, the value of np is 423.1 , which is greater than or equal to 10, and the sample size is stated to be less than or equal to 5% of the population size. (Round to three decimal places as needed. P ( 1 - p ) np np ( 1 - p ) p n Help Me Solve This View an Example Get More Help - Clear All Check Answer2 The following data represent the pH of rain for a random sample of 12 rain dates. A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. Complete parts a) through d) below. 5.58 5.72 5.24 4.80 5.02 4.5 4.7 5.19 4.61 4.76 4.56 6 69 Click the icon to view the table of critical t-values. (a) Determine a point estimate for the population mean. X A point estimate for the population mean is 5.04 . Table of Critical t-Values (Round to two decimal places as needed.) (b) Construct and interpret a 95% confidence interval for the mean pH of rainwater. Select the correct choice below and fill in the answer boxes to complete your choice. cending order. Round to two decimal places as needed.) A. There is 95% confidence that the population mean pH of rain water is between and. O B. There is a 95% probability that the true mean pH of rain water is between |and right tail C. If repeated samples are taken, 95% of them will have a sample pH of rain water between 4.762 and 5.318 1-Distribution Degrees of Area in Right Tail Freedom 0.25 0.20 0.15 0.10 0.05 0.025 0.02 0.01 0.005 0.0025 0.001 0.0605 1.000 -376 1.963 63657 318.3 636.61 0.765 1638 31.599 0.215 8.610 2.015 5.893 0.718 1.134 5.208 5.959 4:501 18 8989 4.207 4.781 4.144 4 587 4.025 4437 4.221 3:733 3.496 067 2576 3 090 Degrees of 0.25 0.20 0.15 0.10 0.05 0.025 0.02 0.01 0.005 0.0025 0.001 0.0605 Freedom 1-Distribution Area in Right Tail Help Me Solve This View an Example Get More Help - All Check AnswerThe data shown below represent the repair cost for a low-impact collision in a simple random sample of mini- and micro-vehicles (such as the Chevrolet Aveo or Mini Cooper). Complete parts (a) through (c). $3184 $1041 $734 $661 $762 $1748 $3394 $2046 $2699 $1360 Click here to view page 1 of the standard normal distribution table Click here to view page 2 of the standard normal distribution table. Click here to view the table of critical t-values. (a) Draw a boxplot to check for outliers. Choose the correct answer below. A. O B. O C. &D Q TTTTTTT TTT TTT TTT TTT 2000 4 4000 o 2000 2000 4000 (b) Construct and interpret a 95% confidence interval for the population mean cost of repair. Does the boxplot suggest that it is reasonable to construct a confidence interval for the population mean? O A. No, the boxplot shows there are outliers. B. Yes, the distribution is roughly symmetric and there are no outliers. O C. No, the distribution is roughly symmetric with no outliers. D. Yes, the distribution is highly skewed with outliers. If the boxplot suggests a confidence interval can be constructed, calculate and interpret the lower bound and the upper bound of the confidence interval. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. (Round to the nearest dollar. Use ascending order.) A. There is a 95% probability that the mean cost of repair is between $ and $ O B. We are 95% confident that the mean cost of repair is between $ and $ O C. The confidence interval should not be constructed. Help Me Solve This View an Example Get More Help - Clear All Check Answer3 (screenshot 2 of 3, to show graphs). The data shown below represent the repair cost for a low-impact collision in a simple random sample of mini- and micro-vehicles (such as the Chevrolet Aveo or Mini Cooper). Complete parts (a) through (c). $3184 $1041 $734 $661 $762 $1748 $3394 $2046 $2699 $1360 X X Standard Normal Distribution Table (Page 1) Standard Normal Distribution Table (Page 2) Table of Critical t-Values - X -Area in ight tai Table VII 1-Distribution Table V Table V (continued) Degrees of Area in Right Tail Standard Normal Distribution Standard Normal Distribution Freedom 0.25 0.20 0.15 0.10 0.05 0.025 0.02 0.01 0.005 0.0625 0.001 0.9065 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 2 0.06 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 1.000 6.314 0.816 1.376 3.078 127.321 318.309 2.920 15,894 63.657 14.089 636.610 $1-599 0.0003 0.0603 0.0003 0.000 0.0003 0.0003 0.0003 0.0003 0.000 0.0002 0.0 0.5000 0.5040 0.5080 .5120 0.5199 0.5239 0.5279 0.5319 0.5359 1638 10.215 0.5160 7:173 -3.3 0.0005 0.0005 0.0005 0.0004 0.0804 0.0804 0.0804 0.0004 0.000 0.0603 .5517 0.5557 0.5596 0.5906 0.5675 0.5714 0.5753 0.920 1476 2:757 4:032 4773 8.610 -3.2 0.0007 0.0007 0.0006 0.0606 0.0006 0.0006 0.0006 0.0005 0.0605 0.5793 0.5832 ).5910 0.5948 0.5987 5.893 0.6026 0.6064 0.6103 0.6141 4.317 5.959 0.0010 0.0009 0.0009 0.0009 0.0008 0.0008 0.0008 0.0008 0.0007 0.0007 0:3 0.6255 0.6293 0.6331 0.6368 0.6406 0.6443 0.6517 4.785 -3.0 0.0013 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 0.0011 0.0010 0.0010 0.4 0.655 0.6591 0.6628 ).6664 0.6700 0.6736 0.6772 .6808 0.6844 D.6879 0.0019 0.0018 0.0018 9.0017 .0016 0.0016 0.0015 0.0015 0.0014 0.0614 0.5 0.6915 0.6950 0.6985 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.7224 4.144 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.0020 0.0019 0.6 0.7257 0.7291 0.7324 0.7357 0.738 0.7422 0.7454 0.7486 0.7517 0.7549 -2.7 0.0035 0.0034 0.0033 0.0032 0.0851 0.0030 0.0029 0.0028 0.0026 0.7580 0.7611 0.7642 0.7673 0.770 0.7734 0.7764 0.7794 0. 7823 0.7852 -2.6 ).0047 0.0045 0.0044 0.0043 0.0041 0.0040 0.0039 0.0038 0.0037 .0036 0.8 0.7910 0.7939 0. 162 0.7967 0.8023 0.8051 0.8078 0.8133 -25 0.0062 0.0060 6coo'0 0.0057 0.0055 0.0054 0.0052 0.0051 0.0049 0.0048 0.9 0.8186 0.8212 .8238 0.7595 0.8264 0.8289 0.8315 0.8340 0.2506 0.8365 0.8389 -2.4 0.0080 0.0078 0.0075 0.0066 0.0064 0.8413 0.8438 0.8461 0.8485 0.850 0.8531 0.8554 0.8577 0.8599 0.8621 -2.3 0.0082 0.0104 0.0673 0.0069 0.0107 0.0102 0.0099 0.0096 -2.2 0.0094 0.0091 0.0089 0.0087 0.0084 0.8643 0.0129 0.0119 0.011 0.864 0.8686 0.8708 0.8729 0.8749 0.8770 0.8810 0.8830 0.0139 0.0136 0.0132 0.0125 0.0122 0.0116 0.0110 0.8849 0.8888 0.8925 0.892 0.8944 0.8962 0.8980 0.8997 0.9015 -2.1 -2.0 ).0179 0.0174 0.0170 0.0166 0.0162 0.0158 0.0154 0.0150 0.0146 0.0143 0.9049 0.9066 0.9082 0.9115 0.9131 0.9147 0.0228 0.0222 0.021' 0.0212 0.0207 0.0202 0.0197 0.0192 0.0188 0.0183 0.9192 0.9207 0.9222 .9236 0.9251 0.9265 0.9279 0.9292 0.9306 0.9319 -1.8 0.0281 0.0768 0.0262 0.0256 0.0250 0.0244 0.0239 0.0233 0.9332 0.9345 0.9357 0.9370 0.938 0.9394 0.0359 0.0551 0.0524 0.0336 0.032 0.0522 0.0314 0.0307 0.0301 0.0294 0.9452 0.9463 0.9474 0.9484 0 9205 0.940 0.9418 0.9429 0.9441 0.9515 0.9535 -1.7 0.0446 0.0427 0.0418 0,0409 0.0401 0.0392 0.0384 0.0275 0.0567 0.9554 0.9564 0.9573 0.9582 0.9591 0.9599 0.960 0.9625 0.9633 -1.6 .0548 0.0537 0.0526 0.0516 0.0505 0.0495 0.0485 .0475 0.0465 0.0455 0.9649 0.9656 0.9664 0.9671 0.9678 0.9686 0.9693 0.9706 -1.5 0.0668 0.0655 0.0643 0.0630 0.0618 0.0606 .0594 0.0502 0.0571 0.0559 0.9713 0.9719 0.9726 .9732 0.9744 0.9750 0.9756 0.9761 0.9767 -1.4 0.0808 0.0793 0.0778 0.0749 0.0721 0.0681 0.9772 0.9778 0.9783 0.9788 0.9798 0.9803 0.9808 0.9812 0.9817 -1.3 0.0968 0.0951 0.0764 0.0934 0.0918 0.0901 0.0885 0.0869 0.0853 0.0638 0.0823 0.9821 0.9826 0.9834 0.9846 0.9854 0.9857 -1.2 0.1131 0.111 0.1093 0.1056 0.1038 0.1020 0.0985 0.986 0.9864 0.9868 0.9871 0.9875 0.9878 0.9881 0.9884 0.9887 0.9890 0.1357 0.1335 0.1314 0.1292 0.1251 0.123 0.1210 0.1170 0.989 0.9896 0.9901 0.9906 0.9909 0.9911 0.0913 -1.0 0.1587 0.1423 0.9918 0.9920 0.9916 0.1562 0.1539 0.151 0.1469 0.144 0.1401 0.1379 0.9922 0.9925 0.9927 0.9929 0.9932 0.9934 0.9936 0.1841 0.1814 0.1788 0.2061 01762 0.1685 0.1660 0.2033 0.1949 0.1635 0.9938 0.9940 0.9941 0.9943 0.9945 0.9946 0 0960 0.9948 0.9949 0.9951 0.9952 0.2119 0.9953 0.9956 0.9959 0 9062 -0.7 0.2090 0.1922 0.1894 0.9%%S 0.9957 0 9061 0.2420 0.2327 0.2236 0.2206 0.9965 0.9966 0.9967 0.9968 0.9969 0.9970 0.9971 0.9972 0.9973 0.9974 -0.6 ).2743 0.256% 0.2858 0.2709 0.2676 0.2643 0.2611 0.2578 0.2546 ).2514 0.2483 0.2451 0.9975 0.9977 -0.5 0.9977 0.9978 0.9979 0.9979 0.9980 0.9981 .3085 0.3050 0.3015 0.2981 0.2946 0.2912 .2877 ).2843 2810 0.2776 0.9981 ).9982 0.9982 0.9983 0.9984 0.9984 .9985 0.9985 0.9986 0.9986 -0.4 .3446 0-2799 0.3512 -363 0.3228 93 02 0.3156 0.3121 0.9987 0.9987 0.998 0.9988 0.9988 0.9989 0.9989 0.9989 0.9990 0.9990 -0.3 0.5621 0.5183 0.3745 0.3707 0.3557 0.3520 0.3483 0.9990 0.9991 0.9742 09092 0.4090 0.9291 76560 0.9993 -0.2 0.4207 0.4168 0.4129 0.3936 0.3897 0.3859 0.9993 0.9993 0.9994 0.9994 0.9994 0.9994 0.9994 0.9995 0.9995 0.9995 -0.1 0.4602 0.4522 0.4483 0.4404 0.4325 0.9995 -0:0 0.4364 0.4247 0.9995 0.9995 0.9996 0.9996 0.9996 0.9996 0.9997 0.5000 0.4960 0.4920 0.4880 0.4840 0.4801 0.4761 0.4721 0.4286 0.4681 0.4641 0.9997 0.9997 0.9997 0.9997 0.9997 0.9997 0.9996 0.9997 0.9997 0.9997 0.9998 Print Done Print Done Print Done Help Me Solve This View an Example Get More Help - Clear All Check Answer4 The trade volume of a stock is the number of shares traded on a given day. The data in the first accompanying table, in millions (so that 6.16 represents 6, 160,000 shares traded), represent the volume of a PepsiCo stock traded for a random sample of 38 trading days in 2018. A second random sample of 38 days in 2018 resulted in the data in the second accompanying table. Complete parts (a) through (d). Click here to view the data for sample 1 Click here to view the data for sample 2. Click here to view the table of critical t-values. (a) Use the data from sample 1 to compute a point estimate for the population mean number of shares traded per day in 2018. Table of Critical t-Values -X A point estimate for the population mean number of PepsiCo shares traded per day in 2018 is 5.54 million. (Round to two decimal places as needed.) (b) Using the data from sample 1, construct a 95% confidence interval for the population mean number of shares traded per day in 2018. Interpret the confidence interval. Select the correct choice below and fill in the answer boxes to complete your choice. Area in (Round to two decimal places as needed.) O A. The number of shares of PepsiCo stock traded per day is between million and million for % of all days in 2018 O B. There is a % probability that the population mean number of shares of PepsiCo stock traded per day in 2018 is between million and million. Table VII f-Distribution O C. One can be % confident that the number of shares of PepsiCo stock traded in all days of 2018 is between million and million. Degrees of Area in Right Tail D. One can be 95 % confident that the population mean number of shares of PepsiCo stock traded per day in 2018 is between 5.07 million and 6.00 million. Freedom 0.25 0.20 0.15 0.10 0.05 0.025 0.02 0.01 0.0025 0.001 0.0605 1.000 1.376 1963 3.078 2.920 12.706 63.657 318.309 636.619 (c) Using the data from sample 2, construct another 95% confidence interval for the population mean number of shares traded per day in 2018. Interpret the confidence interval. 0.816 22.327 31.59 0 741 2.353 10.215 12 924 2.999 7172 Select the correct choice below and fill in the answer boxes to complete your choice. 0.727 2015 3.365 4:032 4.773 5,893 (Round to two decimal places as needed.) 2.757 6.869 2.612 4.317 5.208 5.959 O A. One can be % confident that the population mean number of shares of PepsiCo stock traded per day in 2018 is between million and million. 2.517 2.449 3:833 4 501 5.041 4.297 4781 O B. There is a % probability that the mean population number of shares of PepsiCo stock traded per day in 2018 is between million and million. 2.359 4.144 4.587 2.328 3.497 4.437 O C. One can be % confident that the number of shares of PepsiCo stock traded in all days of 2018 is between million and million. 4318 4.221 O D. The number of shares of PepsiCo stock traded per day is between million and million for % of all days in 2018. 2.249 3.733 4.140 4.073 4.015 3.965 3.883 3.552 3.505 3.792 Sample 1 Volumes (millions) X Sample 2 Volumes (millions) X 3. 745 3.725 3.435 3.707 Sample 1 Sample 2 6.16 4.16 6.12 4.89 4.98 7.54 4.49 10.96 3. 646 5.55 8.88 8.57 5.27 3.633 4.28 7.56 3.65 7.65 3.622 7.28 6 10 6.89 4.96 6.39 4 00 5.73 3.79 3.591 4.02 6.22 6.34 3.582 4.35 4.54 4.64 3.65 4.85 6.69 6.96 4.80 8.13 5.32 6.71 5.08 5.75 5.05 6.85 5.46 4.95 4.13 5.90 4.81 4.42 6 67 4.52 6.69 3.25 6.23 8.37 7.84 4.92 5.00 6.04 4.97 5.44 6.58 5.07 3.94 7.76 6.74 3.291 4.80 5.04 5.99 4.37 6.92 2.42 5.68 3.71 Help Me Solve This View an Example Get5 The trade magazine QSR routinely checks the drive-through service times of fast-food restaurants. A 95% confidence interval that results from examining 519 customers in Taco Bell's drive-through has a lower bound of 156.2 seconds and an upper bound of 160.0 seconds. Complete parts (a) through (c). (a) What is the mean service time from the 519 customers? The mean service time from the 519 customers is 158.1 seconds (Type an integer or a decimal. Do not round.) (b) What is the margin of error for the confidence interval? The margin of error is 1.9 seconds. (Type an integer or a decimal. Do not round.) (c) Interpret the confidence interval. Select the correct choice below and fill in the answer boxes to complete your choice. Type integers or decimals. Do not round.) O A. One can be % confident that the mean drive-through service time of Taco Bell is seconds. O B. The mean drive-through service time of Taco Bell is seconds % of the time. O C. There is a % probability that the mean drive-through service time of Taco Bell is between seconds and seconds. O D. One can be % confident that the mean drive-through service time of Taco Bell is between seconds and seconds. Help Me Solve This View an Example Get More Help - Clear All Check Answer6 In a study, researchers wanted to measure the effect of alcohol on the hippocampal region, the portion of the brain responsible for long-term memory storage, in adolescents. The researchers randomly selected 17 adolescents with alcohol use disorders to determine whether the hippocampal volumes in the alcoholic adolescents were less than the normal volume of 9.02 cm" . An analysis of the sample data revealed that the hippocampal volume is approximately normal with no outliers and x = 8.19 cm and s = 0.7 cm. Conduct the appropriate test at the a = 0.01 level of significance. State the null and alternative hypotheses. Ho: H = 9.02 H1: M 518 (b) Test the hypothesis at the a = 0.10 level of significance. Is a mean math score of 524 statistically significantly higher than 518? Conduct a hypothesis test using the P-value approach. Find the test statistic. to = 2.49 (Round to two decimal places as needed.) Find the P-value. The P-value is. (Round to three decimal places as needed.) Help Me Solve This View an Example Get More Help - Clear All Check Answer9 A simple random sample of size n = 200 drivers with a valid driver's license is asked if they drive an American-made automobile. Of the 200 drivers surveyed, 120 responded that they drive an American-made automobile. Determine if a majority of those with a valid driver's license drive an American-made automobile at the a = 0.05 level of significance. What type of variable is "drive an American-made automobile, or not"? A. Qualitative with two possible outcomes O B. Discrete O C. Continuous O D. Qualitative with more than two possible outcomes What type of hypothesis test is appropriate to conduct for this research? O A. Hypothesis test on a population mean B. Hypothesis test on a population proportion O C. Hypothesis test on a population standard deviation Determine the null and alternative hypotheses. Ho: p = 0.5 H1 : p > 0.5 (Type integers or decimals. Do not round.) Which distribution should be used for this hypothesis test? A. The normal distribution because the parameter is a proportion, p, and the model conditions are satisfied. O B. The normal distribution because the parameter is the mean, o is known, and the model conditions are satisfied. O C. The Student's t-distribution because the parameter is the mean, o is not known, and the model conditions are satisfied. O D. The chi-square distribution because the parameter is o or of, and the model conditions are satisfied. Calculate the test statistic. Test statistic = 2.83 (Round to two decimal places as needed.) Calculate the P-value. P-value = (Round to three decimal places as needed.) X Vi (1,!) More Help Me Solve This View an Example Get More Help - Clear All Check Answer10 Asimple random sample of size n = 15 is drawn from a population that is normally distributed. The sample mean is found to be i = 24.4 and the sample standard deviation is found to be s = 6.3. Determine if the population mean is different from 26 at the a = 0.01 level of signicance. Complete parts (a) through (d) below. (a) Determine the null and alternative hypotheses. H0: p =26 H1: p #26 (b) Calculate the P-value. P-value = (Round to three decimal places as needed.) Help Me Solve This View an Example Get More Help A Clear All 11 through (c) below. Suppose you wish to determine if the mean IQ of students on a certain campus is different from the mean IQ in the general population, 100. To conduct this study, you obtain a simple random sample of 50 students on this campus, administer an IQ test, and record the results. The mean IQ of the sample of 50 students is found to be 106.5 with a standard deviation of 12.6. Complete parts (a) Click the icon to view the t-distribution table. (a) Construct a hypothesis test Ho: H = Ho versus H, : H #Ho for Ho = 102, 103, 104, 105, 106, 107, 108, 109, 110, and 111 at a = 0.05 level of significance. Determine the test statistics for Ho = 102, 103, 104, 105, and 106. Ho = 102 to = 2.53 Ho = 103 to = 1.96 - X 10 = 104 0 = 1.40 Table of Critical t-Values Ho = 105 0 = 0.84 Ho = 106 to = 0.28 (Round to two decimal places as needed.) Determine the test statistics for Ho = 107, 108, 109, 110, and 111. - Area in Ho = 107 to = 1-Distribution Ho = 108 to = Degrees of Area in Right Tai Freedom 0.25 0.20 0.15 0.10 0.05 0.025 0.02 o = 109 to = 0 0.01 0.005 0.0025 0.001 0.0605 1.000 1.376 Ho = 110 to = [ 0.816 1.963 3.078 6.314 12.706 3.657 127.32 2353 4.089 29 327 2132 10.215 Ho = 111 to = 4 032 (Round to two decimal places as needed.) 882 82988 683 0.677 0674 Degrees of 0.25 0.20 0.15 0.10 0.05 0.025 0.02 0.01 Freedom 0.005 0.0025 0.001 0.0605 t-Distribution rea in Right Tai Help Me Solve This View an Example Get More Help - Clear All Check