need help with the following questions

Question 16 (4 points) To test whether the mean time to mix a batch of adhesive is the same for machines produced by four manufacturers, TiteBondMax obtained DATA on the time (minutes) needed to mix the materials. Test whether the machines have equal mean mixing time at (1 = 0.01. O The data provide strong evidence against H0: Equal means at pvalue 0.013. The mixing machines are not all equal. 0 The data provide extreme evidence against H0: Equal means at pvalue 0.001. The mixing machines are not all equal. O None of the answers are correct. 0 The data provide weak evidence against H0: Equal means at pvalue 0.072. Equality of means remains plausible. O The pvalue 0.0001 is extreme evidence that the machines are not all the same. 0 The data provide insignicant evidence against HO: Equal means at pvalue 0.514. The machine are considered equal. Question 17 (4 points) To balance inventory at Otto's Optometry, customer Gender and Eye Condition were collected in DATA. Make a 2x2 pivot table with Gender in rows and Eye Condition in columns. The pivot table is None of the answers match my table Count of Eye Condition Column Labels Row Labels ~Bifocals Farsighted Nearsighted Grand Total Female 22 9 16 47 Male 17 15 5 37 Grand Total 39 24 21 84 Count of Gender Column Labels Row Labels -Bifocals Farsighted Nearsighted Grand Total Female 15 9 20 44 Male 10 15 15 40 Grand Total 25 24 35 84 Count of Eye Condition Column Labels Row Labels - Bifocals Farsighted Nearsighted Grand Total Female 29 17 55 LD LD Male 9 11 29 Grand Total 38 18 28 84 Count of Eye Condition Column Labels ~ Row Labels Bifocals Farsighted Nearsighted Grand Total Female 13 27 5 45 Male 8 24 39 Grand Total 21 51 12 84Question 18 (3 points) Given the following contingency table with category labels A, B, C, X, Y, and 2, what is the expected count with 1 decimal place in the joint category of C and X? X Y Z A 9 10 1 B 15 6 2 C 5 1 5 Your Answer: :] Answer Question 19 (4 points) What is the critical value for level of significance and table parameters in DATA? 22.307 11.143 None of the answers are correct. 18.475 5.991Question 12 (4 points) The Lawnpoke Golf Association (LGA) has established rules that manufacturers of golf equipment must meet for their products to be acceptable for LGA events. BatOutaHell Balls uses a proprietary process to produce balls with a mean distances of 295 yards. BatOutaHell is concerned that if the mean distance falls below 295 yards, the word will get out and sales will sag. Further, if the mean distance exceeds 295 yards, their balls may be rejected by LGA. Measurements of the distances are recorded in DATA. At C1 = 0.05, test the no action hypothesis that the balls have a mean distance of 295 yards. O The test statistic of 1.908 is greater than the critical value of 1.734, therefore H0 is rejected. It is reasonable to assume that the distance is not 295 yards. 0 The test statistic is 1.297 and the critical value is 1.734, therefore the test statistics is less than the critical value and the null hypothesis is not rejected. The distance is about 295 yards. 0 The test statistic is 3.003 and the critical value is 1.734, therefore the test statistic is greater than the critical value of 1.734 and the null hypothesis is rejected. The distance is not 295 yards. 0 The test statistics of 2.238 is greater than the critical value of 1.734, therefore H0 is rejected. it is reasonable to assume that the distance is not 295 yards. Question 13 (4 points) The Fast N' Hot food chain wants to test if their "Buy One, Get One Free" program increases customer traffic enough to support the cost of the program. For each of 15 stores, one day is selected at random to record customer traffic with the program in effect, and one day is selected at random to record customer traffic with program not in effect. The results of the experiment are documented in DATA. For each store, compute difference = traffic with program minus traffic without program. At a = 0.05, test the hypothesis that the mean difference is at most O (at best the program makes no difference, or worse it decreases traffic) against the alternative that the mean difference > 0 (the program increases traffic). None of the answers are correct. The pvalue of 0.033 provides strong evidence against HO. HO is rejected at a = 0.05. You decide to recommend further evaluation of the program. The pvalue of 0.002 provides overwhelming evidence against HO. HO is rejected at a = 0.05. You decide that the program results in increased customer traffic, overall, and recommend the program be implemented. The pvalue of 0.221 indicates that the data provide insignificant evidence against HO. HO is not rejected at a = 0.05. You decide to conclude the study and not to recommend the program. The pvalue of 0.084 provides weak evidence against HO. HO is not rejected at a = 0.05. You decide the evidence is not strong enough to recommend further evaluation of the program. O The pvalue rejects HO: Mean difference > 0.Question 14 (4 points) BigDeal Real Estate surveyed prices per square foot in the valley and foothills of Hoke-a-mo, Utah. Based on BD's DATA, are prices per square foot equal at o = 0.01? O The critical value is 2.977 since this is a two-tail scenario. The test statistic is 1.936. Since the test statistic the critical value, the test statistic does lie in the area of rejection. Reject the null hypothesis. The prices per square foot are not equal at alpha = .01 Question 15 (4 points) National Bearings manufactures bearings at plants located in Portland Oregon, Houston Texas, and Jacksonville Florida. To measure employee knowledge of Total Quality Management (TOM), six employees were randomly selected at each plant and tested. The test scores for these employees are given in DATA. Managers want to know if, on average, knowledge of TOM is equal across the 3 plants. Test equality of mean scores at a = 0.05. O The F value of 9 is > the F critical value of 3.682, therefore reject the equality of means. Knowledge of TOM is not equal across the 3 plants. The F value of 1.326 is the F critical value of 3.682, therefore reject the equality of means. Knowledge of TOM is not equal across the 3 plants