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need help with this question *Course Hero X ta The Expert TA | Human-like Gradi X + X C usb06ca.theexpertta.com/Common/TakeTutorialAssignment.aspx . . . 1. 1D
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*Course Hero X ta The Expert TA | Human-like Gradi X + X C usb06ca.theexpertta.com/Common/TakeTutorialAssignment.aspx . . . 1. 1D Motion Part 1 Begin Date: 2/9/2022 12:01:00 AM -- Due Date: 5/26/2022 11:59:00 PM End Date: 5/26/2022 11:59:00 PM (5%) Problem 19: A detailed graph of position versus time is shown. EXPER 30.0 Assignment Status 20.0 x (km) Click here for detailed view 10.0 Problem Status Completed 1.0 2.0 3.0 4.0 5.0 WNH Completed t (h) Completed 4 Completed 5 Completed 6 Completed 7 Completed 8 Completed 20% Part (a) What is the maximum displacement represented on the graph in km? 9 Completed Tmax = 30 - Correct! 10 Completed 11 Completed 20% Part (b) What is the acceleration at t = 1.1 h in km/h2? 12 Completed a=0 / Correct! 13 Completed 20% Part (c) What is the instantaneous velocity at t = 2.6 h in km/h?*Homework Help - Q&A from Onl X ta The Expert TA | Human-like Gradi X + X C usb06ca.theexpertta.com/Common/TakeTutorialAssignment.aspx . . . 9 Completed max = 30 Correct! 10 Completed 11 Completed 20% Part (b) What is the acceleration at t = 1.1 h in km/h? 12 Completed a = 0 / Correct! 13 Completed 20% Part (c) What is the instantaneous velocity at t = 2.6 h in km/h? 14 Completed v = - 15 15 Completed v = -15 V Correct! 16 Completed 17 Completed 20% Part (d) What is the average velocity during the time interval from 1.55 h to 4.6 in km/h? 18 Completed U = - 9.84 U=-9.84 - Correct! 19 Partial 20% Part (e) What is the average position during the interval from 0.25 h to 4.6 h in km? Grade Summary x = 0 km Deductions 6% Potential 94% sin( cos tan( 7 8 9 HOME Submissions cotan( asin( Attempts remaining: 9 acos() E 4 5 6 (1% per attempt) atan() acotan() sinh() 2 3 detailed view 1% cosh( tanh() cotanh() + 0 END 1% O Degrees O Radians VO BACKSPACE DEI CLEAR AWN 1% 1% Submit Hint Feedback I give up! Hints: 1 for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. -You may think of this as a weighted average. It may be useful to consider how we obtain average velocity from a velocity curve. You may consider how we determine the average of a function in integral calculus. javascript:ETAProbNav.clickPart(18, 0);Homework Help - Q&A from Onl X ta The Expert TA | Human-like Gradi X Course Hero X + X F -> C usb06ca.theexpertta.com/Common/TakeTutorialAssignment.aspx ... Class Management | Help 7. Forces-MotionLaws Begin Date: 3/27/2022 12:01:00 AM -- Due Date: 4/23/2022 11:59:00 PM End Date: 5/27/2022 11:59:00 PM (8%) Problem 9: Suppose you have a 135-kg wooden crate resting on a wood floor. The coefficients of static and kinetic friction here are us=0.5 and MK-0.3. EXPERT Randomized Variables m = 135 kg Assignment Status Click here for detailed view Problem Status Partial Completed UAWNE Partial 50% Part (a) What maximum force, in newtons, can you exert horizontally on the crate without moving it? fmax = 675 7 Correct! *50% Part (b) If you continue to exert this force once the crate starts to slip, what will its acceleration be, in meters per square second? Grade Summary a = Deductions 2% Potential 98% 9 Partial sin( cos() tan( 7 8 9 HOME Submissions 10 Attempts remaining: 13 cotan() asin( acos() 4 5 6 11 (1% per attempt) atan() acotan() sinh() 2 3 detailed viewStep by Step Solution
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