Question
Not allowed to use calculator: Define h : R 2 { ( 0 , 0 ) ] } R as h ( x , y
Not allowed to use calculator: Defineh:R2{(0,0)]}R ash(x,y)=7(x2+y2)cos(x)cos(y) and calculateH(x):=limy0h(x,y) for allxR (also x=0)
Is H a continuous function of x?
What does this say about the possibilities of choosing a value c = h(0,0), such that h become continuousin whole R2?
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Abstract Algebra A First Course
Authors: Dan Saracino
2nd Edition
1478618221, 9781478618225
