NOTE: Most of the time the DQ will time out on you, so you can prepare your text in Word, for an easy copy and paste into the DQ and then embed images as needed. For most if not all of the DQs, you will not be allowed to just attach your Word document as an answer. There are directions(steps) for embedding images given in the module when it is required for the DQ (some, but not all DQs require embedding).

DQ 5 - Background: Read "American Community Survey" summary found on page 635 of our textbook. This is located in the "UNIT E: Exercises" section of our textbook.

Note: For your opening post, we will use a sample of 1000 people, where we found that 861 have health insurance and 139 do not.

Part 1) Using our sample data above,use bootstrapping method (using STATKEY)to generate a 90% confidence interval for the proportion of US residents whodo not havehealth insurance. Give your confidence interval in interpretation form (sentence).

For this part 1) students are required TAKE A PARTIAL SCREEN GRAB (SNIP) of your BOOTSTRAP DISTRIBUTION GRAPH AFTER you have used it to find the 90% CI for p, and be sure to add a title to it "Bootstrap 90% CI for p" and INCLUDE THIS "EMBEDDED IMAGE" in your Part 1 answer, along with the actual PROPER INTERPRETATION (in sentence form as shown in videos.) The endpoints must be shown as part of the graph and If no graph is included, you will see zero credit for part 1, so be sure you have it and UPLOADED that image to Canvas, before being ready to do your "initial post".

Part 2) Using our sample data above, use the appropriate technology usingtraditional methodsto construct a 90% confidence interval for the proportion of US residents whodo not havehealth insurance, this time based off an approximately normal distribution (more traditional method).

Give your confidence interval in interpretation form (sentence in appropriate format/wording as shown).

Part 3 - What is the sample statistic and corresponding margin of error for part (1)? What is the sample statistic and corresponding margin of error for part (2)?

Answer this as well:How does this answer compare to your answer from part (1)? (compare the margin of error (s) , or width of the intervals with specifics and not generalities). Also: Compare point estimates by calculating the difference, not just restating them. Which has a wider interval ; which is more narrow?

Part 4 - What if we found that the sample statistic and the corresponding margin of error based on the ENTIRE American Community Survey(ACS) sample turned out to be a sample proportion is 0.155 with a margin of error of0.0001(for 90% confidence level) again for the entire sample. (important we stay with the results written here).

Q: Why is the margin of error so different from the either of the ones you computed in part (3)?... those margin of errors from part 1 and part 2.

Part 5 - Use the information given in (must use what is said in part 4) to generate and interpret a 90% confidence interval for the true proportion of US residents who do not have health insurance, based on the entire ACS sample based off date given in PART 4.