Now that you are likely drowning in the terminology of mirrors and lenses, let's return to the, likely, most important equation in geometrical optics:

Question

88 users unlocked this solution today!

 

Now that you are likely drowning in the terminology of mirrors and lenses, let's return to the, likely, most important equation in geometrical optics: the relationship among the object distance, 1 image distance, and focal length, i.e., + do di = 1. Thankfully this f" same equation applies to lenses as it does to mirrors. (No derivation required!) If you used a converging ("magnifying") lens to focus the Sun's rays, and since the Sun is very far from the lens so that all its rays incident on the lens lie parallel to the optical axis, where would the image of the Sun be created? (Many of you probably tested this principle in your childhood to burn things!) At its "refracted ray" focal point on the incident light side of the lens. At its "refracted ray" focal point on the outgoing light side of the lens. At its "incident ray" focal point on the outgoing light side of the lens. At its "incident ray" focal point on the incident light side of the lens.