Question: Numeracy applications assessment with given formulas 1 A con was resting on a book / palm . The book / palm was lifted upward from

Numeracy applications assessment with given formulas
1
A con was resting on a book/palm. The book/palm was lifted upward from rest at 0.3ms?s for 0.2 second and the stopped at chest level. Find the max height reached by the coin, measured from the chest level., Formulas say that a=vf-v0t2-t1,a=dvdt. distance =v0**t+a**t t t initial distance, vf =v0+a**t,vf2=v0v2+2**a** distance
2
There was a swinging pendulum. Find the max height of the bob when the bob had 1.5ms maximum speed at the minimum height position called position-A. What would be the speed of the bob at the maximum height position? .Formulas say that KE=0.5**m**v**v,PE=m**9.8**h
The string was cut when the bob was at the max height position, find the time for the falling bob to reach position-A
The string was cut when the bob was at the minimum height position, Find the fallen distance 0.001 second after the cut.
Find the range of the bob when the fallen time to reach ground =1.5 seconds
Was the mass included in any of the equations that you used?
If the mass of the bob was double, would that change the answers above?
3
A 3-kg stone was hurled around moving in a circle by an astronaut in Space with a 2-meter string attachment. The radial acceleration was 0.5ms?s. Find the forces on the stone. Find the fly-off speed
Formulas say that a=v**vR,F=m**a,F=m**dvdt
4
In daily examples of forces like pushing a box, static friction would be overcome in the initial pushing force to start from rest and the smaller kinetic friction could be overcome with a smaller pushing force to keep going. Formulas say that friction = coefficient*Support force
Find the initial pushing force if the static friction coefficient was 0.35 for a 50-kg box on a flat floor (PH201/301/421 Students: Find the initial pushing force if the static friction coefficient was 0.35 for a 50-kg box on an inclined floor of 30 degrees, knowing that sin30=0.5 and cos30=0.866
After starting the motion, the pushing force was reduced by 10%(at 90% level of the initial pushing force). Find the net force on the box when the kinetic friction coefficient was 0.25.
After 5 sec , the engineering situation required a constant speed, find the new pushing force.
5
Impulse pair in collision, that is an example of Newton's third law on two interacting objects. A 4 kg moving at +5ms collided with a 2 kg object at -10ms.=
The exchange impulse was 40 N -sec magnitude and opposite directions.
Find the velocity of the 4- kg object and 2 kg object after collision.
Formulas say that m**vf-m**v0=F** contact time
6
A 10,000kg and 5 cubic-meter object was sitting on a floor. Find the support force of the floor. Formulas say that F-net=m**a
A 10,000kg and 5 cubic-meter object was submerged in a fluid of density of 800 kg per cubic meter. Find the support force of the fluid using the buoyance force formula of fluid density*9.8** displaced volume
Numeracy applications assessment with given

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