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Obtain the exact quadratic factor of the given function below using Bairstow's method with the initial value for r = 3 & s =
Obtain the exact quadratic factor of the given function below using Bairstow's method with the initial value for r = 3 & s = 41 and a terminating condition of Er = Es 0.0255%. f(x) = -0.0143x3 -0.0802x + 1.0597x + 5.476 b3 b2 -0.0143 -0.0143 -0.0143 b1 Roots: (+) x= L: (-)x=_ b0 c3 c2 -0.0143 -0.0143 -0.0143 c1 Ar As
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