Question
On the basis of stoicheometry, justify the answer why 1 mL of 0.025 M of Na2S2O3 is equivalent to 1.0 mg/L of DO? Calculate the
On the basis of stoicheometry, justify the answer why 1 mL of 0.025 M of Na2S2O3 is equivalent to 1.0 mg/L of DO? Calculate the DO value if your 250 mL sample consumes 18 mL of 0.014 M Na2S2O3?
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Intermediate Accounting
Authors: James D. Stice, Earl K. Stice, Fred Skousen
17th Edition
032459237X, 978-0324592375
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