Question
On the left-hand side, for the first term 9x, we have the following.d/dx[9x]=_Now, note that the second term x2y is a product, so we must
On the left-hand side, for the first term 9x³, we have the following.d/dx[9x³]=_Now, note that the second term x2y is a product, so we must use the product rule. We therefore have the following.d/dx[x²y] = (x²)(y') + __
On the left-hand side, for the first term 9x³, we have the following.d/dx[9x³]=_Now, note that the second term x2y is a product, so we must use the product rule. We therefore have the following.d/dx[x²y] = (x²)(y') + __
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Precalculus
Authors: Braja M Das, David Cohen, Theodore B Lee, David Sklar
7th Edition
1133386482, 9781133386483
