On the left-hand side, for the first term 9x, we have the following.d/dx[9x]=_Now, note that the second term x2y is a product, so we must

On the left-hand side, for the first term 9x³, we have the following.d/dx[9x³]=_Now, note that the second term x2y is a product, so we must use the product rule. We therefore have the following.d/dx[x²y] = (x²)(y') + __