One of the chief concerns of using carbon-based fuels is the release of the greenhouse gas CO into the atmosphere. It would be best to use a fuel that releases a lot of heat and the least amount of CO. Using enthalpy of combustions, determine which fuel, glucose (C6H1206) or octane (CsH1s), has a higher heat of reaction per mole of CO2 created. Use the table below of enthalpy of formations and balanced combustion reactions to determine kJ/mole CO for each fuel. Glucose: Octane: Molecule C6H12O6 (Glucose) C8H18 (Octane) CO HO (1) kJ/mole CO kJ/mole CO AH (kJ/mol) -1273.02 -226.61 -393.5 -285.83