One way to synthesize ethylamine (CH, CH,NH,) is from the reaction of ammonia (NH,) with chloroethane (CH,CH,CI). (1) NH3 + CH3CH2Cl CHCH,NH, + HCl One problem with this synthesis route is that the reaction is not very selective, and ammonia may react with two chloroethane molecules to form diethylamine ((CH2CH) NH). (2) NH3 + 2 CH CH CI (CH, CH2)2NH + 2 HCI A mixture of xy = 0.465 mol NH,/mol, x2 = 0.465 mol CH, CH, Cl/mol, and the remainder inerts is fed into a reactor. Within the reactor, the fractional conversion of CH, CH, Cl is 0.770 and the fractional yield of CH, CH NH, is 0.540. [Fractional yield is the (moles of desired product formed)/(moles of product possible for complete conversion of the feed to the desired product).] Assume a 100 mol basis for the feed stream, and calculate the number of moles of each component entering the reactor and leaving in the product stream. Here is the process flow diagram for reference. Reactor 100 mol x, mol NH, /mol x, mol CH CH, Cl/mol x, mol inerts/mol n, mol NH, n, mol CHCH,CI no mol inerts n, mol CH,CH,NH, no mol (CH, CH2)2NH n, mol HCI How many moles of NH, enter the reactor? n = mol NH; How many moles of CH CH, Cl enter the reactor? n2 = mol CH3CH2C1 How many moles of inerts enter the reactor? n3 = mol inerts How many moles of inerts leave the reactor? n6 = mol inerts How many moles of CH, CH, CI leave the reactor? ng = mol CH3CH2CI How many moles of CH CH_NH, leave the reactor? n7 = mol CH3CH2NH2 How many moles of (CH, CH), NH leave the reactor? ng = mol (CH3CH2)2NH How many moles of NH, leave the reactor? n4 = mol NH3 How many moles of HCl leave the reactor? ng = mol HCI