Only E please

(1) Find the critical numbers of f on the given interval and use the rst or second derivative test to label each one as a local minimum, local maximum or neither. Then compute the absolute maximum and absolute minimum values of f on the given interval. (a) x) = 3:1:'1 4.1:" 12:1:2 4- 1 on {2.3} 0)) HI) = a?" + 7 on [-415] (a) f(x) = 1:39: on [0,31 (d) rs) = ln(:.':2 + x +1) on [1,1] (8) a:2+5 :c