onsider an optical fiber as shown in the figure below. There is a core with index of refraction n2 and a cladding of index of refraction n3 < n2. Air outside of the optical fiber is n1 = 1. [THIS QUESTION IS COPYRIGHTED BY PHILIP CHANG 2024] The numerical aperture of the fiber is sin 1, where 1 in the angle of incidence between the air and the core such that the light reflects off the core-clad interface at the critical angle c. Looking at the figure, show that sin 1 = pn2 2 n2