oo AT&T LTE 7:14 AM @ 74% Ci} ( Back Module 7 - Turn-ln Assignment I Detail l Submission Grade Module 7 - Turn-In Assignment Module 7 - Turn-In Assignment Due: Apr 4, 2017, 8:59 PM Path of a Rocket A model rocket is launched with an initial velocity of 11[c] feet per second from the height of [a] feet. The funcfion s(t) = -16t2+ 11[c]t+[a] models the path of the rocket where t represents the time, in seconds, after which the rocket is launched and 5 represents the height of the rocket at time t. Previous Next lou / Q El Courses Calendar To Do Notifications MessagesOOOOO AT&T LTE 7214 AM @ 74% E' < Back Module 7 - Turn-In Assignment Detail Submission Grade 1. Fill in the table of values for the function, and give a short interpretation for each point. 2. How long Will it take for the rocket to return to the ground? 3. How long Will it take the rocket to reach its maximum height? What is the maximum height reached by the rocket? Round all answers to one decimal place. Note: if [a]=2 and [c]=7, then m if) : -1(;r3 -117r+ 2 Work this custom problem about the quadratic function using the techniques you learned in this module. Previous Next CoursesOOOOO AT&T LTE 7217 AM @ 73% li} ( MATH 111 Module 7 Turn-In As... fi Path of a Rocket MBHHMMHMIEMW ' J- Y Li} g ' (II O N O O - - - 150 I- I- I ' N O r o Hou / Q E Courses Calendar To Do Notifications MessagesAnswer 12 Using [a] =3and =7equation .t'(t)=-ltz +l l[c]t+a becomes s(:)=-Iofi+n7z+3 =-l6!2+77l+3 Using this equations(r) = - l6!2 + 77t + 3 fill in the table as s(!) = -l6ll + 77: + 3 interpretation The initial height of rocket is 3 ft 93 The height of rocket after 2 see is 93 it 55 The height of rocket after 4 sec is 55 R The negative value shows. the rocket must hit the ground ahead of IO sec. The max height of rocket is 95.6 ft, so not possible to achieve 150 ft. The max height of rocket is 95.6 ft, so not possible to achieve l50 fi. 200 The max height of rocket is 95.6 ft, so not tossible to achieve 200 fi. 200 The max height of rocket is 95.6 ft, so not ossibie to achieve 200 it. -827 Not possible 150 Not possible 150 Not possible Not possible Answer 2: To find the time t for the rocket 0 return the ground, plug in s(l) = Oand then solve for! as -I(u*+77:+3=0 [a=-16.b=77,c=3] '--771J77'-4(-i6)3 l--btJb3-4ac ' 2-(-16) ' 20 --771J6121 ' -32 -E-Jl621 2+J1621 32 32 '32 32 =-0.04,4.9 Since time cannot be negative, discard the value! = -004. Therefore. the rocket will return to the ground in about Answer 3: Using this equations(l) = - l6!2 + 77t + 3 find the ! coordinate of vertex as b t--- 2a 77 -2(-16) - 77 'E 52.4 Therefore. the rocket will reach to maximum height in about 77 . Plug in t= sand evaluate s(t) = -l6t' + 77: +3 as S(t)= -l6 2) +77[2)+3 x32v 32 -6l21 64 = 95.6 Therefore, the maximum height of rocket is about l95.6 feet]