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Operating systems using linux. Thumbs up for correct answer! Task 1*(100 points) Implement a program that will communicate the value of an integer x, bet

Operating systems using linux. Thumbs up for correct answer!

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Task 1*(100 points) Implement a program that will communicate the value of an integer x, bet ween processes. You can do this using a file to store the value of x, or you can use shared memory with shmget or mmap. Shared memory is out of the scope of this class, so you will have to teach yourself how to use it, however if you put in the effort to learn, it results in simpler more elegant code. x will start with the value 19530, and you must print that value. Then you will loop 5 times where in each loop: the child goes first and subtracts 5 from x, the parent then divides x by 5, and both processes print who they are and their result of x after the operation. If you use a file and not shared memory, then during each iteration of the loop both processes must get the value of x from the file, and store the resulting value of x to the file. wait () is a required function call, so you will need to create a new process, and terminate it each time through the loop The following system calls are required for this lab: fork() wait( The following functions may be useful for this lab: open), read(), write() sleep() : make the process wait for a number of seconds atoi): converts string to integer . sprintf(): can be used to convert integer to string fflush(): forces a file buffer to flush. This is useful to flush stdout before creating a child so you don't have two processes print ing the same buffer to the screen. This can sometimes fix strange printing behavior. Task 1*(100 points) Implement a program that will communicate the value of an integer x, bet ween processes. You can do this using a file to store the value of x, or you can use shared memory with shmget or mmap. Shared memory is out of the scope of this class, so you will have to teach yourself how to use it, however if you put in the effort to learn, it results in simpler more elegant code. x will start with the value 19530, and you must print that value. Then you will loop 5 times where in each loop: the child goes first and subtracts 5 from x, the parent then divides x by 5, and both processes print who they are and their result of x after the operation. If you use a file and not shared memory, then during each iteration of the loop both processes must get the value of x from the file, and store the resulting value of x to the file. wait () is a required function call, so you will need to create a new process, and terminate it each time through the loop The following system calls are required for this lab: fork() wait( The following functions may be useful for this lab: open), read(), write() sleep() : make the process wait for a number of seconds atoi): converts string to integer . sprintf(): can be used to convert integer to string fflush(): forces a file buffer to flush. This is useful to flush stdout before creating a child so you don't have two processes print ing the same buffer to the screen. This can sometimes fix strange printing behavior

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