(OSCAGC06505q040) Can the power property oflogarithms be derived from the power property of exponents using the equation I)" = m? If not, explain why. If 50, show the derivation. 0 Yes' To start, let bx = m. Then log m = at. Next use the power property of exponents: b\" = m => Ufa)" = m\" => b\" = m" Rewrite the exponential with base b b\" = in\" 10g (m\") = xri substituting x = log (m) 10g(m\") = (10g (11%))\" log (m") = n log (m) 0 Yes' To start, let [7" = m. Then 10gb m = x. Next use the power property of exponents: b\" = m => (bx)" = m\" => b\" = m" Rewrite the exponential with base b bmc = m" log!J (m\") = xri substituting x = 10g:I (m) 10gb (m\") = (log) (m)) 10gb (m\") = n log, (m) No, it is not possible because the power property of exponents only applies for postive integer values of m and n. 0 Yes. To start, let bx = m. Then 10gb m = x. Next use the power property of exponents: b\" = 111 => (5')" = m\" => b'DC = m" Rewrite the exponential with base I) b\" = m" 10gb (m") = xn substituting x = log, (m) 10gb (m") = (log, (m)) :1 10gb (m") = n log, (m)