(OSCAGc06s05q028P) Let logs (3) = a and let logs (11) = b. Which method of rewriting log, (55) in terms of a and b is correct? OUse the change-of-base formula to write log; (55) = logs (55 ) logs ( 3 ) By the product rule for logarithms, logs (55) = logs (5 . 11) = logs (5) + logs (11) = 1 + logs (11). Therefore, log3 (55) = _ 1+logs (11) = 1+b log5 (3) Use the change-of-base formula to write log, (55) = logs (55) logs (3) By the product rule for logarithms, logs (55) = logs (5 . 11) = logs (5) + logs (11) = 0 + logs (11). Therefore, log3 (55) = J logs(11) logs (3) a . Use the change-of-base formula to write log; (55) = logs (3) logs (55) By the product rule for logarithms, logs (55) = logs (5 . 11) = logs (5) + logs (11) = 1 + logs (11). Therefore, log3 (35) = - logs (3) 1 +logs ( 1 1) = 1+6 Use the change-of-base formula to write log, (55) = 1085(55) logs (3 ) By the product rule for logarithms, logs (55) = logs (5 . 11) = logs (5) - logs (1 1) = 1 - logs (1 1). Therefore, log3 (55) = - 1-logs (11) log5 (3) 1-6 OUse the change-of-base formula to write log; (55) = logs (55) logs (3) By the product rule for logarithms, logs (55) = logs (5 . 11) = logs (5) . logs (11) = 1 . log5 (11) = logs (11). Therefore, log3 (55) = _logs (11) logs (3)