Out of 300 people sampled, 75 had children. Based on this, construct a 90% confidence interval for the true population proportion of people with children. Preliminary: a. Is it safe to assume that n < 5% of all people with children? Yes No b. Verify np(1-) > 10. Round your answer to one decimal place. np(1-p)=56.25 Confidence Interval: What is the 90% confidence interval to estimate the population proportion? Round your answer to three decimal places.