Question
Output the code in a 100data.txt file after compiling on onlinegdb compiler. Read the integers from the file in an array or linked list. show
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Output the code in a 100data.txt file after compiling on onlinegdb compiler.
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Read the integers from the file in an array or linked list.
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show me the screenshot after it has been compiled and outputted into a 100data.txt file on onlinegdb compiler.
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DO NOT CHNAGE THE CODE.JUST ADD THE CODES THAT IS NECCESSARY TO output it into a 100data.txt file.
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I WILL UPVOTE FOR THE CORRECT ANSWER
#include
// helper function for quick sort int partition(int arr[], int l, int h) { int pivot = arr[h]; int i = (l - 1); //smaller element index
// iterate for array from l to h for (int j = l; j <= h - 1; j++) { // current element smaller than pivot if (arr[j] < pivot) { i++; // swap elements int t = arr[i]; arr[i] = arr[j]; arr[j] = t; } } // swap i+1 and h array index elements int t = arr[i + 1]; arr[i + 1] = arr[h]; arr[h] = t; return (i + 1); } // defination for quicksort function void quickSort(int arr[], int l, int h) { // for left and right index not equal if (l < h) { //pi is partitioning index int pi = partition(arr, l, h);
// recursively iterate till array sorted // divide array into two, sort them seperatly quickSort(arr, l, pi - 1); quickSort(arr, pi + 1, h); } }
// for merge sort, helper merge void merge(int arr[], int l, int m, int r) { // declare required variables int i, j, k; int n1 = m - l + 1; int n2 = r - m; int L[n1], R[n2];
// copy from L to R for (i = 0; i < n1; i++) L[i] = arr[l + i]; for (j = 0; j < n2; j++) R[j] = arr[m + 1 + j];
// merge temp values back to array i = 0; j = 0; k = l; while (i < n1 && j < n2) { if (L[i] <= R[j]) { arr[k] = L[i]; i++; } else { arr[k] = R[j]; j++; } k++; }
// remaining elements of L[] while (i < n1) { arr[k] = L[i]; i++; k++; }
// copy the remaining elements of R[] while (j < n2) { arr[k] = R[j]; j++; k++; } }
// Actual merge sort function void mergeSort(int arr[], int l, int r) { // for left index less than right if (l < r) { // middle index m int m = l + (r - l) / 2;
// Divide into two parts mergeSort(arr, l, m); mergeSort(arr, m + 1, r); // merge both parts merge(arr, l, m, r); } }
// Driver program int main(void) { // Use 191022310 as seed for random generator srand(191022310); int i; // Here i am initializing 100 as size. "CHANGE THE INTEGERS TO 200 AND 300 FOR THE UPCOMING TASKS". int size = 100; int arr[size]; for (int i = 0; i < size; i++) { // initializing the array value with unique random integer arr[i] = rand(); //printing the num printf("%d ", arr[i]); }
// so that merge sort should not get same arr int *array_for_quicksort = arr; // test, implementation sort arr using quicksort clock_t t; t = clock(); // before time quickSort(array_for_quicksort, 0, size - 1); t = clock() - t; //after time double time_taken = ((double)t) / CLOCKS_PER_SEC;
// EXECUTION TIME for quick sort printf(" time taken by quick sort : %f secs ", time_taken );
// sort arr using merge sort clock_t t1; t1 = clock(); mergeSort(arr, 0, size - 1); t1 = clock() - t1; double time_taken1 = ((double)t1) / CLOCKS_PER_SEC;
// EXECUTION TIME for merge sorts printf("time taken by mergeSort: %f secs ", time_taken1 );
return 0; }
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