Over the years, the mean customer satisfaction rating at a local restaurant has been 79. The restaurant was recently remodeled, and now the management claims the mean customer rating, u, is not equal to 79. In a sample of 51 customers chosen at random, the mean customer rating is 81.2. Assume that the population standard deviation of customer ratings is 7.5. Is there enough evidence to support the claim that the mean customer rating is different from 79? Perform a hypothesis test, using the 0.10 level of significance (a) State the null hypothesis /, and the alternative hypothesis .1 (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. . The value of the test statistic is given by - . The p-value is two times the area under the curve to the right of the value of the test statistic. Standard Normal Distribution Step 1: Select one-tailed or two-tailed. One-tailed O Two-tailed Step 2: Enter the test statistic. (Round to 3 decimal places.) Step 3: Shade the area represented by the p- value. (c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the management. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 79