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P Q ~(PQ) ~P Q T T F F T T F T F F F T T T T F F T T F
P | Q | ~(PQ) | ~P | Q |
T | T | F | F | T |
T | F | T | F | F |
F | T | T | T | T |
F | F | T | T | F |
Not both P and Q.
Not P.
Therefore, Q.
Not both P and Q.
Not Q.
Therefore, P.
I cannot be both at home and in the city. I am not at home, therefore I am in the city (denying a conjunct)
Instructor feedback: This is perfect! Just one more step to go - explaining how the truth table shows us that the argument is indeed fallacious.
How does the truth table show that the argument is fallacious?
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